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Solution:

Let the number of second shift workers = x
So, the number of first shift workers =\(\frac{ 2}{3x}\)

Production by each first shift worker = y
Production by each second shift worker=\( \frac{4}{3y}\)

By bringing the above knowledge together, we can form an equation

Total =\(\frac{2}{3}\)xy +\(\frac{4}{3}\)xy

We can get 2xy +\( \frac{4}{3}\)xy = 2xy

Now, we can look for the values for the total production by the first shift workers, which will be 12 among the options available. And when we put that into the equation, we get 12 +\( \frac{4}{3}\)yx

12 + \(\frac{2}{3} \)xy2 = 36(total)

Hence, Total production by first shift workers = 12, and the Number of total light bulbs made by the two shifts = 36
Bismuth83
At a certain factory, the number of first-shift workers is 2/3 the number of second-shift workers. Every day, each second-shift worker can make 4/3 as many light bulbs as each first-shift worker.

In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
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Bismuth83
At a certain factory, the number of first-shift workers is 2/3 the number of second-shift workers. Every day, each second-shift worker can make 4/3 as many light bulbs as each first-shift worker.

In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
let p be the number of first-shift workers
let q be the number of second-shift workers
p = (2/3)q
q = (3/2)p

let x be the unit output of first-shift worker
let y be the unit output of second-shift worker
y = (4/3)x

px = total output of first-shift worker
qy = total out put of second-shift worker

qy = (3/2)p * (4/3)x
= (4/2)px
= 2 px

total number of day's output = px + qy = px + 2px = 3px

so pick the number of total output and first-shift output that has ratio of 3
answer is 12 and 36
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Let the no. of 2nd shift workers be 3. (I have taken 3 since it is the denominator, and will reduce fractions)
So, no. of 1st shift workers is 2. (2/3*3)
Now, let each 1st shift worker make 3 bulbs.
then, each 2nd shift worker makes 4 bulbs. (4/3*3)
so 1st shift = 2*3 = 6
2nd shift = 3*4 =12
total = 6 + 12 = 18
So, ratio of both to first has to be 18:6 (i.e. 3:1). The only possible ans is 36 (both) 12 (1st shift)
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HI Now, let each 1st shift worker make 3 bulbs.
can we assume they make 3 bulbs ?
can you please clarify a bit on this

purplepixie
Let the no. of 2nd shift workers be 3. (I have taken 3 since it is the denominator, and will reduce fractions)
So, no. of 1st shift workers is 2. (2/3*3)
Now, let each 1st shift worker make 3 bulbs.
then, each 2nd shift worker makes 4 bulbs. (4/3*3)
so 1st shift = 2*3 = 6
2nd shift = 3*4 =12
total = 6 + 12 = 18
So, ratio of both to first has to be 18:6 (i.e. 3:1). The only possible ans is 36 (both) 12 (1st shift)
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