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Bunuel
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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's 02 Apr 2025, 00:30
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B
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35% (medium)

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73% (01:54) correct 27% (02:07) wrong based on 158 sessions

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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jalal's weight. Who among these 5 persons weighs the least?

A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena


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B
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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's Updated on: 02 Apr 2025, 07:44
Originally posted by doordash on 02 Apr 2025, 06:56.
Last edited by doordash on 02 Apr 2025, 07:44, edited 1 time in total.
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j = 2m = 2(0.6b) = 1.2b
m = 0.6b
d = 0.5l = 0.5(0.19j) = 0.5(0.19(2m)) = 0.114b
l = 0.19j = 0.19(2m) = 22.8b

thus dolly weighs the least

correct answer is B
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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's 02 Apr 2025, 07:20
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Lets M weight be 100 then
J is twice M. So J is out J=200
M is 60% of B. So B is out since B is more than M
D=L/2 so L is out
L = .19*J =.19*200=38
Ans is Dolly

Ans B
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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's 02 Apr 2025, 13:02
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Bunuel
Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jalal's weight. Who among these 5 persons weighs the least?

A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena


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Even though the Sum can be solved using ratios. Logically it can be ascertained DOLLY is the LEAST.

GIVEN STATEMENTS :

Jalal weighs twice as much as Meena.

J = 2M . Which means J > M.

Meena's weight is 60% of Bahar's weight.

M = 60/100 B , which gives M : B = 3:5 , clearly B > M.

Dolly weighs 50% of Laila's weight.

D weighs half of Laila. Hence, L > D.

Laila weighs 19% of Jalal's weight.

L = 19/100 J . Hence, L : J = 19:100. Therefore J > L.

Our findings till now

J > M.

B > M.

L > D.

J > L. Combining last two eqn we get J > L > D . We need to find relations between B and M.

J = 2M = 2* (3/5) B = 6/5 B. This implies J :B = 6:5 J > B. Using eqn 2, J > B > M.

If we can find a correlation between L and M, we are done.

L = (19/100) J = (19/100)*2M = (19/50)*M . Thus L:M = 19:50. Hence, M > L

Our final equation becomes: J>B>M>L>D

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Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's 02 Apr 2025, 22:41
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Let weight of Meena be x
Meena=x
Jalal=2x, Bahar= 5/3x, Laila=.19*2x=0.38x, Dolly=0.5*0.35x=0.19x

Thus B is the answer
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