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25 Sep 2025, 00:16
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
61% (02:30) correct
39%
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A student gets an aggregate of 60% marks in five subjects in the ratio 10 : 9 : 8 : 7 : 6. If the passing marks are 50% of the maximum marks and each subject has the same maximum marks, in how many subjects did he pass the examination?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
25 Sep 2025, 04:20
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Let the maximum marks be 80 for each subject.
Total maximum marks = 80*5 = 400
Aggregate score = 60% = 400*0.6 = 240
240 aggregate marks in the ratio of 10:9:8:7:6
Therefore marks in each subject = 60, 54, 48, 42, 36.
Passing marks = 50%, which is 0.5*80 = 40, he only achieved less than 40 in one subject out of five, so he must have passed 4 subjects
Ans. D IMO
Total maximum marks = 80*5 = 400
Aggregate score = 60% = 400*0.6 = 240
240 aggregate marks in the ratio of 10:9:8:7:6
Therefore marks in each subject = 60, 54, 48, 42, 36.
Passing marks = 50%, which is 0.5*80 = 40, he only achieved less than 40 in one subject out of five, so he must have passed 4 subjects
Ans. D IMO
25 Sep 2025, 08:09
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Bunuel
The five subjects are in the ratio 10x : 9x : 8x : 7x : 6x
Total marks earned = 10x + 9x + 8x + 7x + 6x = 40x
Let the maximum marks be M = 200.
For five subjects the maximum marks are 5M = 5*200= 1000.
Aggregate 60% means = marks scored / total score
40x / 5M = 60/100
x/M = (3/40).
x = (3/40)*200 = 15.
Then the individual subject marks = 10x = 10*15 = 150.
9x = 9*15 = 135
8x = 8*15 = 120
7x = 7*15 = 105
6x = 6*15 = 90.
Pass mark = 50% M = 50%(200) = 100.
Subject Marks more than pass mark are : 150, 135, 120, 105.
Totally 4 subjects.
