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23 Oct 2025, 00:14
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
67% (01:47) correct
33%
(02:08)
wrong
based on 153
sessions
History
Date
Time
Result
Not Attempted Yet
Out of a group of 8 candidates competing for 2 job positions, 3 will be selected for the final interview. Out of the 3, two candidates will be finally selected. If X is one of the candidates competing, what is the probability that X will not be finally selected?
A. 1/8
B. 1/6
C. 1/4
D. 2/3
E. 3/4
A. 1/8
B. 1/6
C. 1/4
D. 2/3
E. 3/4
ariyanak
Joined: 27 Aug 2024
Last visit: 17 Apr 2026
Posts: 14
Given Kudos: 54
Location: Bangladesh
Schools: Yale Booth (Chicago) Wharton UVA Darden
GMAT Focus 1: 645 Q82 V83 DI80 
GPA: 3.29
23 Oct 2025, 04:12
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Total possible selections = 8C3*3C2 = 168
Selections where X is always selected = 7C2*2C1 = 42
Total Possibilities = 1 -(42/168) = 3/4
Selections where X is always selected = 7C2*2C1 = 42
Total Possibilities = 1 -(42/168) = 3/4
23 Oct 2025, 06:57
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Bunuel
8 candidates are there, out of which 3 is selected = 8C3 = 56
Amongst the three selected , we need to select 2 = 3C2 = 3
Total cases = 56*3 = 168
Probability of X being NOT SELECTED = 1 - ( Probability of X being Selected )
Probability of X being selected, at round 1: X is selected, out of the remaining 7 we need to select 2
7C2 = 21
At round 2, we have X along with two other candidates. X has to be selected amongst the two.
X is selected, out of the 2 candidates one is being selected = 2C1 = 2
Total cases = 21*2 = 42
Probability of X being selected = 42/168 = 1/4
Probability of X not being selected = 1 - (1/4) = 3/4
Option E
