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Bunuel
Tom's age is T years, which is also the sum of the ages of his three children. His age N years ago was twice the sum of their ages then. What is T/N?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


­
Let the current ages of Tom’s children’s be a,b,c respectively.

Tom’s current age = T

Therefore, T = a+b+c

(T-N) = 2* ( a-N + b-N + c -N)

T - N = 2 * ( a+b+c - 3N)

substituting T = a+b+c

T - N = 2 * ( T - 3N)

T - N = 2T - 6N

5N = T

(T/N) = 5

Option D
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Given, Tom's age = T years
sum of his three children's ages = T years (same of his age)

Let the number of years ago = N

Now, Tom's age N years ago will be = T - N
sum of children's age N years ago = T - 3N

Now as per the question,
His age N years ago was twice the sum of their ages then.
i.e. T-N = 2(T-3N)

Solving the equation:-
T-N = 2T -6N
T = 5N

and, T/N = 5:1 i.e. 5
Correct Answer:- (D) 5
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