Bunuel
Deconstructing the Question Target: Find the number of packages weighing
> 420 grams.
Let the weights of the \(n\) packages be \(w_1, w_2, \dots, w_n\).
Analyze Statement (1) "The average (mean) weight is equal to the weight of the lightest package."
Let \(w_{min}\) be the lightest weight.
Equation:
\(\mu = w_{min}\).
Theory: Mean vs Min The mean of a set is always \(\ge\) the minimum value.
The mean equals the minimum value
if and only if all elements in the set are equal.
(Proof: If even one element were greater than \(w_{min}\), the sum would increase, pulling the average above \(w_{min}\)).
So, Statement (1) implies:
All packages have the exact same weight. However, we do not know what that weight is (could be 10g, could be 1000g), nor do we know how many packages there are.
INSUFFICIENT Analyze Statement (2) "The median weight is 410 grams."
This tells us the central value is 410.
It does not restrict the values above the median.
Example A: \(\{410, 410, 410\}\). Count > 420 is 0.
Example B: \(\{400, 410, 500\}\). Count > 420 is 1.
INSUFFICIENT Combine Statements (1) and (2) From (1): All packages have the same weight, let's call it \(W\).
From (2): The median is 410.
If all numbers in a set are \(W\), the median must also be \(W\).
Therefore, \(W = 410\).
This means
every single package in the depot weighs exactly 410 grams.
Question: How many packages weigh more than 420 grams?
Answer:
Zero (since \(410 < 420\)).
Since we can answer with a unique number (0), the statements are sufficient.
SUFFICIENT Answer: C