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3/10 of 120, i.e. 36 ranked A first
2/3 of these 36 people, i.e. 24 ranked B second. Therefore, remaining 12 ranked B last.

11/30 of 120, i.e. 44 ranked B first.

Remaining 120 - (36+44) = 40 people ranked C first
3/4 of these 40 people, i.e. 30 people ranked B second. Therefore, remaining 10 ranked B last.

Total 12 + 10 = 22 people ranked B last. Therefore, Answer is Option D.
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Ranked A first = 36. Ranked B second = 24. Hence ranked B third = 12
Ranked B first = 44
Ranked C first = 120-80=40. Ranked B second = 30. Hence ranked B third = 10
Total = 12 + 10
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In a marketing survey, 120 people were asked to rank three new advertisement designs A, B, and C from most favorite to least favorite. Each person gave a complete ranking with no ties. Of these people, 3/10 ranked design A first and 11/30 ranked design B first. Among those who ranked A first, two-thirds ranked B second. Among those who ranked C first, three-quarters ranked B second. How many people ranked B last?

Total number of people = 120
Number rof people who ranked A first = (3/10)*120= 36
Out of these 36 people, (2/3) ranked B second = (2/3)*36=24
Number of people who ranked A first but ranked B last= 36-24= 12 people

Number of people who ranked B first = (11/30)*120= 44

Number of people who ranked C first = Total number of people- who ranked A first - who ranked B first = 120-36-44= 40
Out of these 40 people, (3/4) ranked B second = (3/4)*40= 30
Number of people who ranked B last= 40-30= 10 people

Total number of people who ranked B last = 12+10 = 22

D. 22
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With A first there are 36 (120*3/10) people. From them, there are 24 (36*2/3) people with B second, so there are 12 people with B last.

With B first there are 44 (120*11/30) people.

So there are 120-36-44=40 people with C first. From them, there are 30 (40*3/4) people with B second, so there are 10 people with B last

People with B last = 12 + 10 = 22

IMO D
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AXX = 36 people
ABC = 36*2/3=24
ACB = 36-24=12

BXX = 44

CXX = 120-36-44=40
CBA = 40*3/4=30
CAB = 40-30=10

ACB + CAB = 12+10=22

Answer D
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A first = 120*3/10 = 36
A first and B second = 36*2/3 = 24
A first and C second and B last = 36 - 24 = 12

B first = 120*11/30 = 44

C first = 120-36-44 = 40
C first and B second = 40*3/4 = 30
C first and A second and B last = 40 - 30 = 10

A first and C second and B last + C first and A second and B last = 12 + 10 = 22

The answer is D
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Three-tenths of the people ranked A first => 30% of 120 = 36

11/30 of them ranked B first => 44 of them

=> No. of people who ranked C first = 120-(36+44) = 40

Out of the 36 who ranked A first, 2/3rds ranked B second => 1/3rd of them ranked B last = 12

Out of the 40 who ranked C first, 3/4ths ranked B second => 1/4th of them ranked B last = 10

Therefore, answer = 10+12 = 22
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Completing with the information:

A first: 3/10 of 120 = 36
+ B second (C third): 2/3 of 36 = 24
+ B third (C second): 36-24 = 12

B first: 11/30 of 120 = 44

C first: 120-36-44 = 40
+ B second (A third): 3/4 of 40 = 30
+ B third (A second): 40-30 = 10

There are 12+10=22 peple who ranked B third.

The correct answer is D
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The Correct Answer for this question is Option D.

So there are 120 people in the survey and each give ranks to all the 3 products A,B and C.

For First place:-

A ---> 3/10 * 120 = 36
B ---> 11/30 * 120 = 44
C ---> 120 - 36 - 44 = 40

For Second Place for B: 2/3 * 36 + 3/11 * 40 = 24 + 30 = 54

So now for the last place of B:- 120 - First place - second Place
120 - 44 - 54 = 22

So the correct answer is 22
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The question can be visualized as a ranking tree, where A->B->C & A->C->B is one tree with two branches.
For B to be last, the focal point cannot be B (B->A...). Hence we only need to consider branches which start with A and C.

Number of people that ranked B last in A branch:

A first = 3/10*120 = 36
Out of these, 2/3 ranked B 2nd, so 1/3 ranked b last = 36*1/3 = 12

Number of people that ranked B last in C branch:
C first = 120-(A first+B first) = 120 - (36 + 11/30*120) = 40
3/4 out of these ranked B 2nd, 1/4 ranked B last = 1/4 * 40 = 10

Total people ranking B last = 12+10 = 22 => D
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Total sts: 120

Ranked first:

A: 3/10 = 36, Now 2/3 of 36 sts ranked B second = 24, then 1/3rd would have ranked it third = 1/3*36 = 12
B: 11/30 = 44.
C: Remaining sts = 40, Now 3/4 of 40 ranked B second = 30, then remaining ranked it third = 10

Hence sts who ranked B third are 12 + 10 = 22

Ans D
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the answer is 20 given 120 people are in total
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A1 = 36
b1 = 44
c1 = 120-a1-b1 = 40

number of people who ranked b2 would be an overlap between those who ranked a1 and c1 => 54

number who ranked b last => 120 - b1 - b2 = 120-44-54 = 22
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We have to find how many has ranked B third.
Afirst=36 Bsecond=2/3*36=24 Csecond= 36-24= 12
So Airst=24, Bsecond=24, Cthird=24 and Afirst=12, Csecond=12, Bthird=12

Bfirst= 11/30*120=44
Cfirst= 120-36-44=40, Bsecond=3/4*40=30, Athird=30
Cfirst=10, Asecond=10,Bthird=10

So Bthird=12+10=22
Answer is D.
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