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18 Dec 2025, 10:13
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IMO B
Prime on both dices would be (2,2), (2,3), (2,5)..... so basically total 9.
outcomes with atleast one prime would be= total- both primes= 36-9 = 27.
probability= favourable/total= 9/27= 1/3.
Prime on both dices would be (2,2), (2,3), (2,5)..... so basically total 9.
outcomes with atleast one prime would be= total- both primes= 36-9 = 27.
probability= favourable/total= 9/27= 1/3.
18 Dec 2025, 10:29
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Total number of Possible factor: No. of possible outcome which have atleast one prime number= (1,2),(1,3),(1,5),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,2),(4,3),(4,5),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,5)= 27 Nos.
Requried outcome= Both dice have even no.= (2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)=9 Nos.
Hence, Probability= 9/27= 1/3
Requried outcome= Both dice have even no.= (2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)=9 Nos.
Hence, Probability= 9/27= 1/3
18 Dec 2025, 10:30
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conditional probability: P(A intersection B)/P(B) where P(B) is at least one prime and P(A intersection B) is both prime.
prime dice: {2,3,5} -> 3/6 = 1/2
P(B) = 1 - (none prime) = 1 - (1/4) = 3/4
P(A intersection B) = 1/4
required probability: 1/4 * 4/3 = 1/3
prime dice: {2,3,5} -> 3/6 = 1/2
P(B) = 1 - (none prime) = 1 - (1/4) = 3/4
P(A intersection B) = 1/4
required probability: 1/4 * 4/3 = 1/3
