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Bunuel
At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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using s1)
this could have a agent with no tickets while other had differnet tickets
example = 0 2 3 4 5 6 8

usning s2)
thic could also have agent with no tickets
example = 0 1 4 4 6 6 7

using s1 and s2) only 1 case is possible
- 1 2 3 4 5 6 7
hence and is C , using both we can conclude there all received atleast 1 ticket.
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7 agents and 28 customers

(1) each agent was assigned a different number of tickets.
The agent could have reciprocated 0,1,2,3,6,7,9 or 0,1,3,4,5,7,8 tickets....there are many possibilities
Insufficient

(2) The agent who was assigned the most tickets was assigned 7 tickets.
It could be 0,0,0,7,7,7,7 or 1,2,3,4,5,6,7.....many possibilities
Insufficient

(1)&(2)
All tickets are different and maximum is 7.
Only 1 possibility: 1,2,3,4,5,6,7
Sufficient

C
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Bunuel
At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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7 Agents
28 tickets
We need to answer if Each Agent go at least 1 ticket?

Statement 1:
Each agent got different no of tickets so it can happen that :
A1 to A7 - anyone got any number of ticket... Might happen that A1 got all 28 tickets and all others got none. Can't Say. Not Sufficient.

Statement 2 :
It says highest ticket to 1 agent is 7.
Lets saty A1=7 tickets
A2=6 tickets
A3= 6 tickets
A4= 6 tickets
A5=3 tickets
A6 & A7 got none.

OR

Any arrangement can be done where other agents get lesser tickets than 7 but that doesnt mean we can confirm everyone got at least one ticket. Not Sufficient.

Combine :

Each got different number of tickets and highest no of tickets to one agent is 7..
7+6+5+4+3+2+1=28

Answer should be C.
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Tickets = 28

S1
The distribution could be 1,2,3,4,5,6,7 which gives Yes OR
The distribution could be 0,2,3,4,5,6,8 which gives NO
Insufficient

S2
The distribution could be 0,0,0,7,7,7,7 which gives No
The distribution could be 1,2,3,4,5,6,7 which gives Yes
Insufficient

Combined, the only distribution which satisfies both is 1,2,3,4,5,6,7
Sufficient

Answer C


Bunuel
At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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Each ticket given to exactly one agent and 28 tickets in total.

1. Different number of tickets to each agent.
Consider scenario where agents got 0,1,2,3,4,5,13 tickets OR 0,1,2,3,4,6,12 OR 1,2,3,4,5,6,7 OR any combination in between
We cannot say that each got at least 01 ticket
Hence, 1 alone is not sufficient.

2. Max that an agent got is 7. Distribution can be 7,7,7,7,0,0,0 OR 7,7,7,6,1,0,0 OR any other. Therefore, 2 alone is not sufficient.

Combining both statements,
Max that an agent got is 7 and each got different number, i.e. 7,6,5,4,3,2,1.
This is the only combination possible. Hence both statement together are sufficient.

Answer Option C
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At a customer support center, 7 agents worked a particular evening shift.
Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent.

Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
Case 1: Number of tickets assigned = {1,2,3,4,5,6,7} = 28 tickets
Case 2: Number of tickets assigned = {0,1,2,3,4,5,13} = 28 tickets
Not sufficient

(2) The agent who was assigned the most tickets was assigned 7 tickets
Case 1: Number of tickets assigned = {1,2,3,4,5,6,7} = 28 tickets
Case 2: Number of tickets assigned = {0,0,0,7,7,7,7} = 28 tickets
Not sufficient

(1) + (2)
(1) Each agent was assigned a different number of tickets
(2) The agent who was assigned the most tickets was assigned 7 tickets
Number of tickets assigned = {7,6,5,4,3,2,1} = 28 tickets
Each agent was assigned at least 1 ticket
Sufficient

IMO C
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SO THE THEE ARE 7 AGENTS AND 28 CUSTOMERS THIS IS A YES/NO QUESTION

1) SAYS A DIFFERENT NUMBER OF THICKET IS ASIGNED AND LEAVES THE POSSIBILITY OF ASIGNING 0 TICKET TO AN AGENT COZ NO CLERIFICATION. SO 50% CHANCE IS NO A SURE ANSWER
2) SAYS THAT 7 IS THE HIGHEST SO IF WE DO A TRIAL OF 7+6+5+....+1= 28
ALSO NOTE THAT THE SATEMENT ARE NEVER INCONSISTENT WWITH EACH EATHER OR OF OPPOSITE NATURE.
B IS OUR ANSWER
Bunuel
At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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Bunuel
At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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Statement (1):
The tickets to every agent must be distinct
ex1: everyone has atleast 1 ticket: 1,2,3,4,5,6,7 -> sum 28
ex2: One agent has 0 ticket: 0,1,2,3,4,8,10 -> sum 28
Statement 1 is not sufficient

Statement (2):
The max is 7 tickets per agent
ex1: 1,2,3,4,5,6,7 -> sum=28
ex2: 0,2,3,3,6,7 -> sum=28

Using (1) and (2) together:
there's only one way
{1,2,3,4,5,6,7}

Hence both are sufficient together

Option C
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I selected C.

Statement (1) - If each agent was assigned a different number of tickets, we could distribute as follows:
0, 1, 2, 3, 4, 8, 10
OR
1, 2, 3, 4, 5, 6, 7
Multiple cases of Yes/No. Therefore, NS.
Statement (2) - If the agent who was assigned the most tickets was assigned 7, that limits the maximum number of tickets we can assign to the rest of the agents to 6. Still, with 6 remaining slots, we can assign 3*6=18+7=25, and in the three remaining agents, we could assign the remaining 3 tickets as we please, so again it is insufficient.

(1) + (2) Sufficient
Looking at it together, with 7 available slots of different integers and the greatest integer being 7, we can see that !+2+3+4+5+6+7 = 28. There is not an alternative way to distribute these tickets within the given constraints, so the answer is yes.
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statement 1 says each was assigned diff number of tickets. we can't find whether each got atleast 1 ticket hence insufficient
statement 2 says max ticket is 7 there can be a ppossibility that a person can have 0 tickets assigned hence insufficient.

both statement is sufficient to check if all have assigned atleast 1 ticket.
hence option c is answer
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if we write the equation then

a + b + c+ d+ e+ f+ g = 28

now
statement 1 says all has different number then zero is also possible hence not sufficent
statement 2 says maximum is 7, now if we take statement 1 together then
all will be assigned ticket from 1,2,3,4,5,6,7 which totals 28

Hence C ...both statement taken together are required.
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Statement I
Each of 7 agents received different tickets.
0+1+2+3+4+5+13 = 28 (each agent received at least one = NO)
1+2+3+4+5+6+7 = 28 (each agent received at least one = YES)
Not sufficient information to answer.
Statement II
Max ticket can be assigned to an agent is 7.
7+7+7+7+0+0+0=28 (each agent received at least one = NO)
1+2+3+4+5+6+7=28 (each agent received at least one = YES)
Not sufficient information to answer.

I+II together.
1+2+3+4+5+6+7 = 28 (different and max 7) Sufficient to answer each received at least one ticket.
Answer (C)
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1. Two agents can take 10,8 each & others as 4,3,2,1,0. On the other hand, each agent can take 4 each.. NOT SUFFICIENT
2. Maximum by 1 is 7. so one agent gets 7, one 5, remaining 4 agents each 4, and one zero. i.e., 7,5, 4,4,4,4,0..NOT SUFFICIENT

together

Only option is 7,6,5,4,3,2,1...SUFFICIENT

Ans C
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(1) not sufficient
the amounts could be, for example, 0,1,2,3,4,6,12
this information alone does not guarantee that EVERY agent had at least one ticket (because ONE agent could have 0)

(2) not sufficient
the amounts could be 7,6,6,6,3,0,0
some agents could still have 0 tickets

(1) and (2) sufficient
the only possible amounts are 0,1,2,3,4,5,6,7
one agent MUST have 0 tickets

answer C together they are sufficient, but neither alone is sufficient
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(1) Each agent was assigned a different number of tickets.
One case can be (1,2,3,4,5,6,7) : sum=28
Another case can be (0,1,2,3,4,5,13) : sum= 28
Thus, Not sufficient.

(2) The agent who was assigned the most tickets was assigned 7 tickets
One case can be (1,2,3,4,5,6,7) : sum = 28
Another case can be (0,0,3,5,6,7,7) : sum = 28
Thus, Not sufficient.

(1) & (2) Combined:
Clearly, there can only be 1 case : (1,2,3,4,5,6,7)
Thus, Sufficient.

Answer: C
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At a customer support center, 7 agents worked a particular evening shift. Exactly 28 customer tickets were assigned during the shift to the agents, and each ticket was assigned to exactly one agent. Did each agent receive at least 1 ticket assignment?

(1) Each agent was assigned a different number of tickets.
(2) The agent who was assigned the most tickets was assigned 7 tickets.

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We have to assign 28 tickets among 7 agents

Statement 1 - Since each agent was assigned a different number, one case can be 0,1,2,3,4,5,13 or 1,2,3,4,5,6,7. Since the answer to the question differs in these two cases with a no and a yes respectively , the statement is insufficient

Statement 2- The maximum assigned was 7 tickets. Similar to above, there can be cases made where agents with 0 tickets can be in the set and on the other hand, where every agent is assigned atleast 1 ticket. Insufficient

Combining both the statements, we can say that 1,2,3,4,5,6,7 is the only case possible and the question can be answered definitively.

Therefore, Option C
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given: 28 customer tickets were assigned to 7 agents with a constraint that no ticket was assigned to more than one agent.
did each received at least one ticket or none got zero assignment?
1. each got different no. of tickets
0,2,3,4,5,6,8
1,2,3,4,5,6,7 since both distributions satisfy the conditions----insufficient
2. the agent with most assignments got 7 tickets
0,3,3,4,5,6,7
1,2,3,4,5,6,7 since both distributions satisfy the conditions ---insufficient
together 1 and 2 are sufficient as can be 1,2,3,4,5,6,7 distribution only.
hence C
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