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Assuming the total number of annual passes issued is 100

Activation Status : 15% were never activated , meaning 85% were activated .

Pass type (Of Activated passes)
Family passes : 40% of 85 = 34 passes.
Individual Passes : 60% of 85 = 51 passes.

Value for A (Family passes)
To Find the percentage of all passes issued that are Family passes and fewer than 6 times.
calculation= 21/34 x 34 = 21

Value for B ( Individual passes)
1/3 x 51 = 17
A: 21
B: 17
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Smart number: 100 people in total
15 ppl: not activated
85 ppl: activated
- family: 85*0.4=34 ppl => 21 ppl used less than 6 times a month
- inidividual: 85*0.6=51 ppl => 17 ppl used less than 6 times a month
=> A=% family: 21%, B=%inidvidual: 17%
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A = \(\frac{85}{100}*\frac{40}{100}*\frac{21}{34}*100\) = 21
Of 85% of activated passes, 40% were family passes; of these 40%, 21/34 were passes that were used less than 6 times.

B = \(\frac{85}{100}*\frac{60}{100}*[farction]1/3[/farction]*100\) = 17
Of 85% of activated passes, 60% were individual passes; of these 60%, 1/3 were passes that were used less than 6 times.

A = 21, B = 17
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
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Let x be the no. of passes issued. If 15% are not activated passes , 85% are activated passes. So , no of activated passes = 0.85x
No. of family passes = 0.4*0.85x
No of Individual passes = 0.6*0.85x
No of family passes used fewer than 6 times a month = (21/34)*0.4*0.85x = 0.21x
No of Individual passes used fewer than 6 times a month = (1/3)*0.6*0.85x = 0.17x

So A = 21% , B=17%.
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
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We can assume the total passes to be 100. From the given problem, 85 of them were activated. Of these, 34 were family passes and 51 Individual passes.

Again, 21/34*34 =21 family passes were used less than 6 times and

1/3*51=17 individual passes were used less than 6 times.

Therefore, A = 21 and B = 17
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Total passes = a:
- 0.15a not activated
- 0.85a activated, including
+ 0.4*0.85a Family, which 0.4*0.85a*21/34 = 0.21a used fewer than 6 times during the month => 21%
+ 0.6*0.85a Individual, which 0.6*0.85a*1/3 = 0.17a used fewer than 6 times during the month => 17%
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
Let the total number of passes issued be N

Total activated passes = 85 * N / 100

Total Family passes = 0.4 * 85 * N / 100 = 34 * N / 100

Total Individual passes = (85 - 34) * N / 100 = 51 * N / 100

Total Family passes used fewer than 6 times = 21 * 34 * N / 100 * 34 = 21 * N / 100
From here we get A = 21

Total Individual passes used fewer than 6 times = 51 * N / 100 * 3 = 17 * N / 100
From here we get B = 17
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Let museum issue 100 passes, 15% activated, 85% not activated.

=> Family passes => 40% of 85 => 34
=> individual passes => 60% of 85 => 51
=> family passes used fewer than 6 times => 21/34y*34 = 21 => A= 21%
=> individual passes used fewer than 6 times = 1/3*51 = 17 => B=17%
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Total passes issued=T
1-0.15=0.85 (85%)
activated 40% r family, 60% r individuals
family passes 0.85X0.40=0.34
individual passes 0.85X0.60=0.51
A=0.34X(21/34)X100=21
B=0.54X(1/3)100=17
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Select for A and for B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.

---Let's consider Museum issues 100x passes

Activated passes = 85x
Family Passes = .40*85x = 34x
Individual Passes = 0.60 * 85x = 51x

Activated Passes used fewer than 6 times during the month = (21/34)*34x+ (1/3)*51x = 21x+17x = 38x

A = 21x/100x = 21%
B = 17x/100x = 17%
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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.

Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.

Let, total number of passes issued= 100
15% of passes were never activated, hence, 85% of passes were activated.
Number of family passes= 40% of 85 = 0.40*85= 34
Number of individual passes= 60% of 85= 0.60*85= 51

Number of family passes that were used fewer than 6 times = (21/34)*34= 21
Number of individual passes that were used fewer than 6 times = (1/3)*51= 17

A=21
B=17
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Activated passes = 85%

A. 40% are family passes = 40% of 85
Of this, 21/34 used it less than 6 times = (40/100) x 85 x (21/34)
= 21%

B. 60% are individual passes = 60% of 85 = 51
Of this, 1/3 were used less than 6 times = 51 x 1/3 = 17%
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Let the total number of passes be x

We know that,
15% of the passes never activated = 0.15x
85% of the passes were activated = 0.85x

From the activated passes,
40% is family = 0.4*0.85x = 0.34x
60% is individual = 0.6*0.85x = 0.51x

Now among these activated passes, some of them were used fewer than 6 times in a month
21/34 of the family passes used lesser than 6 times = 0.34x * (21/34) = 0.21x = 21% of the total passes
1/3rd of the individual passes used lesser than 6 times = 0.51x * (1/3) = 0.17x = 17% of the total passes


A. 21
B. 17
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Assume total passes is 100; 15% never activates to 100 -15= 85% activated
Family pass: 40% of 85= 34
Individual pass: 60% of 85= 51
Fewer than 6 times: Family pass= 21/34 x 34=21
Fewer than 6 times: individual pass= 1/3 x 51= 17
So ; A =21
B = 17
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P = number of annual passes

0.15P never activated -> 0.85P activated

Family passes = 0.4*0.85P
Individual passes = 0.6*0.85P

Family passes used fewer than 6 times = 21/34 * 0.4*0.85P = 0.21P -> 21%
Individual passes used fewer than 6 times = 1/3 * 0.6*0.85P = 0.17P -> 17%

A=21
B=17
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15% are not activated therefore, total active = 85 %

Consider total passes 100, since % is asked
Family passes = 40% of 85
Individual passes = 60% of 85

of these, the passes used fewer then 6 times for family = 85 X 40/100 X 21/34 = 21
for individuals = 85 X 60/100 X 1/3 = 17
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assume total pass issued as X

FP = 0.85 * 40/100 = 0.34X
IP = 0.85 * 60/100 = 0.51X

Now less than 6 pass/months used =
FP less than 6 month = 0.34X * 21/34 = 0.21X
IP less than 6 month = 0.51X *1/3 = 0.17X

Therefore the percentage for

FP less than 6 month/total pass issue = 0.21X * 100/X = 21%
IP less than 6 month/total pass issue = 0.17X/X * 100 = 17%

Hence A = 21
B =17
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