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You can find the answer by trying out different cases of the value of x.

1. x >= 5

x-5+x-1<2
2x<8
x<4 => Wrong

2. 1<=x<5

5-x+x-1<2
4<2 => Wrong

3. x<1
5-x+1-x<2
6-2x<2
2x>4
x>2 => Wrong

Answer: 0 values of x
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I used critical points, not sure if this is the correct approach but did help me get a faster and cleaner answer

1. |X-5| < 2 so 3 < x < 7
2. |X-1| < 2 so -1 < x < 3

Since there is no overlap in the value of X between the 2 sets X = 0
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