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A delivery van traveled from Westport Depot to Lakeview Market in 7 hours. If the trip consisted of a 4-hour first leg at one constant speed and a 3-hour second leg at a different constant speed, what was the van’s average (arithmetic mean) speed for the entire trip?
(1) If the van had traveled for 8 hours at its first-leg speed and for 6 hours at its second-leg speed, it would have traveled 700 kilometers.
(2) If the van had traveled for 1 hour at each of those two speeds, it would have traveled 110 kilometers.
(1) If the van had traveled for 8 hours at its first-leg speed and for 6 hours at its second-leg speed, it would have traveled 700 kilometers.
(2) If the van had traveled for 1 hour at each of those two speeds, it would have traveled 110 kilometers.
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M47-173
05 Jun 2026, 02:00
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GMAT Club Official Solution:
A delivery van traveled from Westport Depot to Lakeview Market in 7 hours. If the trip consisted of a 4-hour first leg at one constant speed and a 3-hour second leg at a different constant speed, what was the van’s average (arithmetic mean) speed for the entire trip?
Let r be the van’s speed during the first leg, and let s be the van’s speed during the second leg.
The actual trip consisted of 4 hours at speed r and 3 hours at speed s, so the total distance was:
4r + 3s
Since the trip lasted 7 hours, the average speed for the entire trip was:
(4r + 3s)/7
So we need the value of 4r + 3s.
(1) If the van had traveled for 8 hours at its first-leg speed and for 6 hours at its second-leg speed, it would have traveled 700 kilometers.
This gives:
8r + 6s = 700
Divide by 2:
4r + 3s = 350
Therefore, the average speed for the entire trip was:
350/7 = 50 kilometers per hour
Sufficient.
(2) If the van had traveled for 1 hour at each of those two speeds, it would have traveled 110 kilometers.
This gives:
r + s = 110
This does not determine the value of 4r + 3s.
Not sufficient.
Answer: A.
A delivery van traveled from Westport Depot to Lakeview Market in 7 hours. If the trip consisted of a 4-hour first leg at one constant speed and a 3-hour second leg at a different constant speed, what was the van’s average (arithmetic mean) speed for the entire trip?
Let r be the van’s speed during the first leg, and let s be the van’s speed during the second leg.
The actual trip consisted of 4 hours at speed r and 3 hours at speed s, so the total distance was:
4r + 3s
Since the trip lasted 7 hours, the average speed for the entire trip was:
(4r + 3s)/7
So we need the value of 4r + 3s.
(1) If the van had traveled for 8 hours at its first-leg speed and for 6 hours at its second-leg speed, it would have traveled 700 kilometers.
This gives:
8r + 6s = 700
Divide by 2:
4r + 3s = 350
Therefore, the average speed for the entire trip was:
350/7 = 50 kilometers per hour
Sufficient.
(2) If the van had traveled for 1 hour at each of those two speeds, it would have traveled 110 kilometers.
This gives:
r + s = 110
This does not determine the value of 4r + 3s.
Not sufficient.
Answer: A.
General Discussion
28 May 2026, 02:32
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We need to find avg speed which is Total distance/ total time.
1) here we can use distance is directly proportional to time if speed is constant. So if respective time has been doubled then the original total distance would be 700/2 i.e 350
now we know total distance and total time so avg speed would be 350/7 sufficient.
2) here, we can't find the relation between distance and time directly.
even if we go by equations. 1st equation would be x+y = 110 and 2nd from question stimuli is 4x+3y = unknown. Not sufficient.
Answer is A
1) here we can use distance is directly proportional to time if speed is constant. So if respective time has been doubled then the original total distance would be 700/2 i.e 350
now we know total distance and total time so avg speed would be 350/7 sufficient.
2) here, we can't find the relation between distance and time directly.
even if we go by equations. 1st equation would be x+y = 110 and 2nd from question stimuli is 4x+3y = unknown. Not sufficient.
Answer is A
