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Bunuel
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let time taken by B to assemble W boxes be= X hours, therefore time taken by A to assemble W boxes=X+5 hours
given- it taken 2 hours for the machines together to assemble 1.5W boxes = 2/1.5 hours to assemble W boxes= 4/3 hours

[*]plugging in our values gives
[*]1/x+1/x+5=3/4
[*]3x^2 + 7x - 20 = 0
[*]
3x^2 + 12x - 5x - 20 = 0

x + 4 = 0(x = -4) doesn't work.
[*]
3x - 5 = 0 , X=5/3 hours

Time taken to cover 2w work=2*5/3=10/3 hours

3 hours 20 min (D)




Bunuel
Machine A takes 5 hours longer than machine B to assemble \(w\) matchboxes. If machines A and B, working together, assemble \(1.5w\) matchboxes in 2 hours, how long does machine B require to assemble \(2w\) matchboxes?

(A) 1 hrs 40 mins

(B) 2 hrs 40 mins

(C) 3 hrs

(D) 3 hrs 20 mins

(E) 4 hrs
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