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16 Jul 2026, 07:18
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t to a is 3/4
t to n is 9/16
a to c is 6/4=3/2
Putting everything in terms of t:
a=4t/3
n=16t/9
c=2a/3=8t/9
t=9a
a=12a
n=16a
c=8a
The three-digit number is 102
t+c=9a+8a=17a less than 102 only if a is less than 6
a is an integer, so a is 5
a+n=12a+18a=28a=28*5=140
The answer is C
t to n is 9/16
a to c is 6/4=3/2
Putting everything in terms of t:
a=4t/3
n=16t/9
c=2a/3=8t/9
t=9a
a=12a
n=16a
c=8a
The three-digit number is 102
t+c=9a+8a=17a less than 102 only if a is less than 6
a is an integer, so a is 5
a+n=12a+18a=28a=28*5=140
The answer is C
16 Jul 2026, 07:19
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T:A is 3:4
T:N is 3/4 if it = 9:16
A:C is twice of T:A = 3:2
Combining it is
T:A:N:C is 9:12:16:8
T+C = (9+8)x = 17x < 102 => x<6
For max case, x=5
A+N = 28x = 140
(C) is the answer
T:N is 3/4 if it = 9:16
A:C is twice of T:A = 3:2
Combining it is
T:A:N:C is 9:12:16:8
T+C = (9+8)x = 17x < 102 => x<6
For max case, x=5
A+N = 28x = 140
(C) is the answer
16 Jul 2026, 07:29
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My ans is C.) 140
Combining the ratios we get-
T:A:N:C
9:12:16:8
It is given T+C= 9x+8x<102; x<6
A+N= 12x+16x= 28x
as x<6; 28x< 28*6; A+N < 168
Max possible option below 168 is 140. (28*5=140)
Combining the ratios we get-
T:A:N:C
9:12:16:8
It is given T+C= 9x+8x<102; x<6
A+N= 12x+16x= 28x
as x<6; 28x< 28*6; A+N < 168
Max possible option below 168 is 140. (28*5=140)
Bunuel
