Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sept. 6, 9:30am-12:30pm EST- Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Oct. 13, 2026 - Jan. 7, 2027, 8:00pm-10:00pm EST
17 Jul 2026, 11:08
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
73% (03:33) correct
27%
(03:20)
wrong
based on 77
sessions
History
Date
Time
Result
Not Attempted Yet
A high-speed train and a regular train each travel between two cities that are 450 miles apart. The high-speed train completes the trip 2 hours faster than the regular train and travels 80 miles per hour faster than the regular train. If a passenger travels from one city to the other on the high-speed train and returns on the regular train, what is the total travel time?
A. 5 hours 40 minutes
B. 6 hours
C. 6 hours 30 minutes
D. 6 hours 40 minutes
E. 7 hours
A. 5 hours 40 minutes
B. 6 hours
C. 6 hours 30 minutes
D. 6 hours 40 minutes
E. 7 hours
17 Jul 2026, 21:09
Kudos
Bookmarks
Rate problems with a "faster by X and quicker by Y hours" setup are honestly one of my favorite GMAT traps because the algebra is simple once you set it up, but almost nobody sets it up cleanly the first time.
1. Let the regular train's speed be r mph. Distance is fixed at 450 miles, so regular train's time is 450/r hours.
2. High-speed train goes r+80 mph, and its time is 2 hours less than the regular train's time. So: 450/(r+80) = 450/r - 2.
3. Move things around: 450/r - 450/(r+80) = 2. Combine into one fraction over a common denominator, the r terms cancel in the numerator, leaving 450 x 80 = 36000 on top.
4. So 36000 = 2r(r+80), which simplifies to r^2 + 80r - 18000 = 0.
5. Quadratic formula: discriminant is 6400 + 72000 = 78400, square root is 280. r = (-80+280)/2 = 100.
6. Regular train speed is 100 mph, time is 450/100 = 4.5 hours. High-speed train is 180 mph, time is 450/180 = 2.5 hours. Check: 4.5 - 2.5 = 2, matches.
7. The question asks for total travel time going one way on the high-speed train and coming back on the regular train, so you add both legs: 2.5 + 4.5 = 7 hours.
Answer is E.
The trap I see most with this type is people solve for r, feel done, and either report just one leg's time or subtract instead of add because the problem mentioned "faster." Read the last line of the question twice, it's asking for the round trip, not the difference.
1. Let the regular train's speed be r mph. Distance is fixed at 450 miles, so regular train's time is 450/r hours.
2. High-speed train goes r+80 mph, and its time is 2 hours less than the regular train's time. So: 450/(r+80) = 450/r - 2.
3. Move things around: 450/r - 450/(r+80) = 2. Combine into one fraction over a common denominator, the r terms cancel in the numerator, leaving 450 x 80 = 36000 on top.
4. So 36000 = 2r(r+80), which simplifies to r^2 + 80r - 18000 = 0.
5. Quadratic formula: discriminant is 6400 + 72000 = 78400, square root is 280. r = (-80+280)/2 = 100.
6. Regular train speed is 100 mph, time is 450/100 = 4.5 hours. High-speed train is 180 mph, time is 450/180 = 2.5 hours. Check: 4.5 - 2.5 = 2, matches.
7. The question asks for total travel time going one way on the high-speed train and coming back on the regular train, so you add both legs: 2.5 + 4.5 = 7 hours.
Answer is E.
The trap I see most with this type is people solve for r, feel done, and either report just one leg's time or subtract instead of add because the problem mentioned "faster." Read the last line of the question twice, it's asking for the round trip, not the difference.
03 Aug 2026, 23:03
Kudos
Bookmarks
here's how i did it-
1. started by finding out factor pairs of 450:
450 = 2 x 3^2 x 5^2
now, starting from 1, whenever a number divides 450 evenly write down the number and the partner. doing this we get,
= 50, 75, 90, 100, 150, 180, 225
2. identify pair with a difference of 80 mph: 100 and 180
3. check time taken-
now, the time difference is: 4.5 - 2.5 = 2 hours (this matches our problem)
Hence, total time taken is 7 hours.
1. started by finding out factor pairs of 450:
450 = 2 x 3^2 x 5^2
now, starting from 1, whenever a number divides 450 evenly write down the number and the partner. doing this we get,
= 50, 75, 90, 100, 150, 180, 225
2. identify pair with a difference of 80 mph: 100 and 180
3. check time taken-
- by regular train: [450][/100]= 4.5 hours
- by high speed train: [450][/180]= 2.5 hours
now, the time difference is: 4.5 - 2.5 = 2 hours (this matches our problem)
Hence, total time taken is 7 hours.
kevincan
