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Question Stats:
87% (02:20) correct
13%
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It takes 50 seconds for Pump A, 60 seconds for Pump B, and 100 seconds for Pump C to each pour 100 gallons of water into a certain lake at their constant rates, respectively. Approximately how many seconds will it take for all three pumps, A, B, and C, to pour 1,000 gallons of water into the lake together at their constant rates?
A. 188
B. 194
C. 214
D. 232
E. 241
Source: Math Revolution
A. 188
B. 194
C. 214
D. 232
E. 241
Source: Math Revolution
26 Aug 2026, 02:03
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Water poured by pump A in 1 second (that is, rate of pump A) = 100/50 = 2
Water poured by pump B in 1 second = 100/60 = 5/3
Water poured by pump C in 1 second = 100/100 = 1
Total water poured in 1 second = 2 + 5/3 + 1 = 14/3 gallons
Total water poured in x seconds = 1000 gallons
Thus, x = (1000*3) / 14 = 214 approx.
Answer is C.
Water poured by pump B in 1 second = 100/60 = 5/3
Water poured by pump C in 1 second = 100/100 = 1
Total water poured in 1 second = 2 + 5/3 + 1 = 14/3 gallons
Total water poured in x seconds = 1000 gallons
Thus, x = (1000*3) / 14 = 214 approx.
Answer is C.
26 Aug 2026, 03:02
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100 g/50 = 2g/s ; 100g/60s= 5/3 g/s; 100/100=1
total water poured in 1 sec = 2+5/3+1 = 14/3 g/s
to pour 1000 gallons = 1000/14/3 = 1000*3/14=3000/14= 214 sec
total water poured in 1 sec = 2+5/3+1 = 14/3 g/s
to pour 1000 gallons = 1000/14/3 = 1000*3/14=3000/14= 214 sec
