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555-605 (Medium)|   Algebra|         
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yuefei
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If s is the product of the integers from 100 to 200 inclusiv Updated on: 18 Feb 2014, 02:21
Originally posted by yuefei on 25 Oct 2007, 17:13.
Last edited by Bunuel on 18 Feb 2014, 02:21, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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D
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If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
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D
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If s is the product of the integers from 100 to 200 inclusiv 25 Oct 2007, 19:10
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yuefei
IF s is the product of integers from 100 to 200, inclusive, and t is the product of integers from 100 to 201, inclusive, what is 1/s + 1/t in terms of t?

A. (201)^2 / t
B. [(202)(201)]/t
C. 201/t
D. 202/t
E. [(202)(201)]/t^2
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D

s = 100*...*200
t = 100*...*200*201
This means
s = t/201
Therefore,
1/s + 1/t = 201/t + 1/t = 202/t
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If s is the product of the integers from 100 to 200 inclusiv Updated on: 22 Aug 2014, 00:01
Originally posted by PareshGmat on 04 Mar 2014, 22:47.
Last edited by PareshGmat on 22 Aug 2014, 00:01, edited 1 time in total.
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Answer = D

s = 100*...*200
t = 100*...*200*201
t = s * 201

So, \(s = \frac{t}{201}\) & \(\frac{1}{s} = \frac{201}{t}\)

Therefore,

\(\frac{1}{s} + \frac{1}{t} = \frac{201}{t} + \frac{1}{t} = \frac{202}{t}\)
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If s is the product of the integers from 100 to 200 inclusiv 25 Oct 2007, 22:06
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I get D..

s=100*...200
t=100*...201, basically t=201*s

s=t/201

1/s=201/t

201/t + 1/t= 202/t
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If s is the product of the integers from 100 to 200 inclusiv 26 Oct 2007, 01:41
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yuefei
IF s is the product of integers from 100 to 200, inclusive, and t is the product of integers from 100 to 201, inclusive, what is 1/s + 1/t in terms of t?

A. (201)^2 / t
B. [(202)(201)]/t
C. 201/t
D. 202/t
E. [(202)(201)]/t^2
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D.

t = 201s or s = t/201

1/s + 1/t = 201/t + 1/t = 202/t
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If s is the product of the integers from 100 to 200 inclusiv 21 Aug 2014, 22:54
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If you become confused for big numbers, just take easy numbers as example.
Here, Let s= 2*3 and t = 2*3*4 ,

So t= s*4 or S= t/4. Similarly in the actual problem
s =t/201. 1/s = 1/(t/201) or 1/s = 201/t
1/s + 1/t = 201/t + 1/t = 202/t
Answer-D
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If s is the product of the integers from 100 to 200 inclusiv 22 Aug 2015, 06:44
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yuefei
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
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s=t/201
1/s + 1/t = 201/t + 1/t = 202/t
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If s is the product of the integers from 100 to 200 inclusiv 08 Oct 2016, 13:09
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yuefei
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
Show more

We are given that s is the product of the integers from 100 to 200 inclusive and that t is the product of the integers from 100 to 201 inclusive. Thus, we know the following:

s x 201 = t

s = t/201

We must determine the value of 1/s + 1/t in terms of t. Since we know that s = t/201, we can substitute t/201 for s in the expression 1/s + 1/t:

1/(t/201) + 1/t

201/t + 1/t

202/t

Answer: D
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If s is the product of the integers from 100 to 200 inclusiv 08 Oct 2017, 12:09
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yuefei
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
Show more

Ans D

1/100*..200 + 1/(100*..201) =1/S

(since 1/100*..200=201/t => 1/S=201/t)

201/t+1/t= 202/t
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If s is the product of the integers from 100 to 200 inclusiv 15 Sep 2019, 19:21
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yuefei
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
Show more

s=200!/99!
t= 201!/99!= 201s
1/s = 201/t
1/s + 1/t = 201/t+1/t= 202/t

IMO D

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If s is the product of the integers from 100 to 200 inclusiv 06 Oct 2020, 00:45
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s = 100 * 101 * ..... * 200
t = 100 * 101 * ..... * 200 * 201

=> t = s * 201

=> s = \(\frac{t}{ 201}\)

\(\frac{1}{s}\) + \(\frac{1}{t }\)

=> \(\frac{1}{\frac{t}{201}}\) + \(\frac{1}{t}\)

=> \(\frac{201}{t}\) + \(\frac{1}{t}\)

=> \(\frac{202 }{ t}\)

Answer D
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If s is the product of the integers from 100 to 200 inclusiv 23 Oct 2020, 18:24
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S is the product of the integers from 100 to 200 inclusive.
T is the product of the integers from 100 to 201 inclusive.

\(T = S * 200\)
\(S = \frac{T}{200}\)

\(\frac{1}{s} + \frac{1}{t} =\)

= \(\frac{1}{T/200} + \frac{1}{T} = \frac{201}{T} + \frac{1}{T} = \frac{202}{T}\)

Answer is D.
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If s is the product of the integers from 100 to 200 inclusiv 26 Sep 2021, 22:53
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s = 100*...*200
t = 100*...*200*201
i.e t = s/201

putting the value of t in given eq.

201/t +1/t = 202/t
answer-D
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If s is the product of the integers from 100 to 200 inclusiv 17 Nov 2025, 03:59
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