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# If s is the product of the integers from 100 to 200 inclusiv

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Manager
Joined: 02 Aug 2007
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If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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Updated on: 18 Feb 2014, 02:21
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If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2
[Reveal] Spoiler: OA

Originally posted by yuefei on 25 Oct 2007, 17:13.
Last edited by Bunuel on 18 Feb 2014, 02:21, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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25 Oct 2007, 19:10
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yuefei wrote:
IF s is the product of integers from 100 to 200, inclusive, and t is the product of integers from 100 to 201, inclusive, what is 1/s + 1/t in terms of t?

A. (201)^2 / t
B. [(202)(201)]/t
C. 201/t
D. 202/t
E. [(202)(201)]/t^2

D

s = 100*...*200
t = 100*...*200*201
This means
s = t/201
Therefore,
1/s + 1/t = 201/t + 1/t = 202/t
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25 Oct 2007, 22:06
I get D..

s=100*...200
t=100*...201, basically t=201*s

s=t/201

1/s=201/t

201/t + 1/t= 202/t
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26 Oct 2007, 01:41
yuefei wrote:
IF s is the product of integers from 100 to 200, inclusive, and t is the product of integers from 100 to 201, inclusive, what is 1/s + 1/t in terms of t?

A. (201)^2 / t
B. [(202)(201)]/t
C. 201/t
D. 202/t
E. [(202)(201)]/t^2

D.

t = 201s or s = t/201

1/s + 1/t = 201/t + 1/t = 202/t
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Re: IF s is the product of integers from 100 to 200, inclusive, [#permalink]

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17 Feb 2014, 10:29
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Hi,
thanks.
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Re: IF s is the product of integers from 100 to 200, inclusive, [#permalink]

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18 Feb 2014, 02:22
seabhi wrote:
Hi,
thanks.

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Done. Thank you.
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If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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Updated on: 22 Aug 2014, 00:01
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s = 100*...*200
t = 100*...*200*201
t = s * 201

So, $$s = \frac{t}{201}$$ & $$\frac{1}{s} = \frac{201}{t}$$

Therefore,

$$\frac{1}{s} + \frac{1}{t} = \frac{201}{t} + \frac{1}{t} = \frac{202}{t}$$
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Originally posted by PareshGmat on 04 Mar 2014, 22:47.
Last edited by PareshGmat on 22 Aug 2014, 00:01, edited 1 time in total.
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Re: If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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21 Aug 2014, 22:54
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If you become confused for big numbers, just take easy numbers as example.
Here, Let s= 2*3 and t = 2*3*4 ,

So t= s*4 or S= t/4. Similarly in the actual problem
s =t/201. 1/s = 1/(t/201) or 1/s = 201/t
1/s + 1/t = 201/t + 1/t = 202/t
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Re: If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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22 Aug 2015, 06:44
yuefei wrote:
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2

s=t/201
1/s + 1/t = 201/t + 1/t = 202/t
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Re: If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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08 Oct 2016, 13:09
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yuefei wrote:
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2

We are given that s is the product of the integers from 100 to 200 inclusive and that t is the product of the integers from 100 to 201 inclusive. Thus, we know the following:

s x 201 = t

s = t/201

We must determine the value of 1/s + 1/t in terms of t. Since we know that s = t/201, we can substitute t/201 for s in the expression 1/s + 1/t:

1/(t/201) + 1/t

201/t + 1/t

202/t

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Re: If s is the product of the integers from 100 to 200 inclusiv [#permalink]

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08 Oct 2017, 12:09
yuefei wrote:
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?

A. 201^2/t
B. 202*201/t
C. 201/t
D. 202/t
E. 202*201/t^2

Ans D

1/100*..200 + 1/(100*..201) =1/S

(since 1/100*..200=201/t => 1/S=201/t)

201/t+1/t= 202/t
Re: If s is the product of the integers from 100 to 200 inclusiv   [#permalink] 08 Oct 2017, 12:09
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