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12 May 2010, 07:23
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:12) correct
27%
(02:21)
wrong
based on 872
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Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.
(1) n = p
(2) There are 5 more students in class K than in class L.
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24 Apr 2023, 00:25
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AntonioGalindo
The second statement is no sufficient by itself. The OA is C, not B, which you can check under the spoiler in the original post.
Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
The stem gives that K = 7n and L = 6p + 1, and asks to find the value of L.
(1) n = p
The above is clearly insufficient.
(2) There are 5 more students in class K than in class L.
K = L + 5;
7n = (6p + 1) + 5;
7n = 6p + 6.
Infinitely many values of n and p satisfy this. For example, (n, p) can be (6, 6), (12, 13), (18, 20), and so on.
(1)+(2) Since from (1) n = p, from (2) we get 7p = 6p + 6, giving p = 6. Consequently, L = 6p + 1 = 37. Sufficient.
Answer: C.
General Discussion
15 May 2010, 12:01
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k= 7n
l=6p+6
1) is insufficient as the eq k=7n & l=6p +1 cannot be solved
2) insufficient as 7n=6p+6 cannot be resolvd
but if we combine these two then we get p=6
hence C
l=6p+6
1) is insufficient as the eq k=7n & l=6p +1 cannot be solved
2) insufficient as 7n=6p+6 cannot be resolvd
but if we combine these two then we get p=6
hence C
