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\(\frac{35}{3}x+\frac{85}{7}(100-x)=1210\)

Can you pls explain the Right hand side of equation.
Won't it be 12.10
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GMATD11
\(\frac{35}{3}x+\frac{85}{7}(100-x)=1210\)

Can you pls explain the Right hand side of equation.
Won't it be 12.10

The equation equates the total selling price. He gets $12.10 i.e. 1210 cents.
If he sold x oranges for 35/3 cents and (100-x) for 85/7 cents, this is a total of
(35/3) * x + (85/7) * (100-x) cents. You equate cents to cents.

Also, you can use the weighted average formula here:

w1/w2 = (85/7 - 121/10)/(121/10 - 35/3) = 9/91

Total 9+91 is 100. So he sells 9 oranges at 35 for 3 and 91 oranges at 85 for 7.
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GMATD11
\(\frac{35}{3}x+\frac{85}{7}(100-x)=1210\)

Can you pls explain the Right hand side of equation.
Won't it be 12.10

Hi,

Because we are taking all the values in cents so we have converted $12.10 into cents which is 1210 cents.
as 1 cent =0.01 Dollar

Hope this helps.

Try and fail but never fail to try.
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for such question need a will power to take on some random complicated numbers. i derived the equation but goofed up with the numbers :(
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simple question.... killer calculation.. WOW...


rxs0005
A woman sold 100 oranges at $12.10, some at the rate of 3 for 35 cents and the rest at 7 for 85 cents. How many were sold at the first rate?

A. 45
B. 21
C. 9
D. 15
E. 12
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Let quantity of 35 cent be X and for 85 cent be Y. So X should be multiple of 3 and Y be 7 respectively.
C. X-9, Y-91 the only option satisfies the condition.

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Solution :

3 oranges sold for 35 would be 35/3 and 7 for 85 would be 85/7.

now forming the equation:

35/3*x + 85/7*y = 1210 cents

x+y = 100

Now substitute the values for x from the answers given.

all the choices given are multiples of 3 - so we know 35/3*x would be integer.

Check the second one 85/7 * (100 - x)

Only when x=9 , y = 91 which is divisible by 7.

So Answer = C
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