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07 Aug 2010, 11:27
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HI this is my first post and it is regarding a question I have on MGMAT Flashcards.
I am currently going through the Geometry flashcards and came across a question that i can't seem to grasp. If you have access to the flashcards it is question 12/23.
I tried linking the image of the question below. Again, my first post, so i dont know if i did this correctly.
What I do not understand is that in the conclusion of the explanation it says angle PRQ is 60 degrees, but then the answer is that angle PRQ is 30 degrees? Am i missing something here? If this is the wrong forum please forward me to the correct forum.
thanks
In the explanation
I am currently going through the Geometry flashcards and came across a question that i can't seem to grasp. If you have access to the flashcards it is question 12/23.
I tried linking the image of the question below. Again, my first post, so i dont know if i did this correctly.
What I do not understand is that in the conclusion of the explanation it says angle PRQ is 60 degrees, but then the answer is that angle PRQ is 30 degrees? Am i missing something here? If this is the wrong forum please forward me to the correct forum.
thanks
In the explanation
Attachment:
geometry.png
(also attached),Attachment:
geometryex.png
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
07 Aug 2010, 13:41
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Here is my attempt to answer the question.
Given angle PQO = 60 degree. Since PR is the diameter of the circle and O is the center of the circle. Therefore length of PO = PR = OQ = radius of the circle.
Also angle PQR = 90 degree and PQR is a right angled triangle.
Since PQO is 60 degree and PO = QO, therefore angle QPO is also 60 degree.
In the triangle PQR, angle PQR = 90 degree, angle QPR = 60 degree
Hence angle PRQ = 180 - (angle PQR + angle QPR)
angle PRQ = 180 -(90+60) = 30 degree.
-----------------------------------------------------------------------------------------------------------------------
The penultimate line in the flash card should read as
Therefore, angle QPR equals 60 degree, so angle PRQ = 180 degree - 90 degree - 60 degree = 30 degree.
Given angle PQO = 60 degree. Since PR is the diameter of the circle and O is the center of the circle. Therefore length of PO = PR = OQ = radius of the circle.
Also angle PQR = 90 degree and PQR is a right angled triangle.
Since PQO is 60 degree and PO = QO, therefore angle QPO is also 60 degree.
In the triangle PQR, angle PQR = 90 degree, angle QPR = 60 degree
Hence angle PRQ = 180 - (angle PQR + angle QPR)
angle PRQ = 180 -(90+60) = 30 degree.
-----------------------------------------------------------------------------------------------------------------------
The penultimate line in the flash card should read as
Therefore, angle QPR equals 60 degree, so angle PRQ = 180 degree - 90 degree - 60 degree = 30 degree.
07 Aug 2010, 13:43
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Welcome to GMAT Club Chesbik!
For any math questions, please post them in the PS or DS forum: gmat-problem-solving-ps-140/
I have moved your post here.
Good Luck.
For any math questions, please post them in the PS or DS forum: gmat-problem-solving-ps-140/
I have moved your post here.
Good Luck.
