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Train A and B, 455 miles apart, are traveling toward each ot
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07 Oct 2013, 05:26
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70% (02:41) correct 30% (03:01) wrong based on 246 sessions
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Train A and B, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train A left at 4 pm traveling at a speed of 60 miles per hour, and train B left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other? A. 7:20 pm B. 8:55 pm C. 9:05 pm D. 9:20 pm E. 9:25 pm Any faster approaches? train A travels for an hour and 45 mins so 7/4. distance travelled = 7/4 * 60 = 105.
since they track is 455 miles and Train A has travelled 105 miles. Now 350 miles left.
Since when they meet distance would be equal so 60t + 45t = 350
t = 10/3 so its 3 hours and 20 mins + 5 : 45 = 9:05 pm
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Re: Train A and B, 455 miles apart, are traveling toward each ot
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07 Oct 2013, 06:40
fozzzy wrote: Train A and B, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train A left at 4 pm traveling at a speed of 60 miles per hour, and train B left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other?
A. 7:20 pm B. 8:55 pm C. 9:05 pm D. 9:20 pm E. 9:25 pm
Any faster approaches?
train A travels for an hour and 45 mins so 7/4. distance travelled = 7/4 * 60 = 105.
since they track is 455 miles and Train A has travelled 105 miles. Now 350 miles left.
Since when they meet distance would be equal so 60t + 45t = 350
t = 10/3 so its 3 hours and 20 mins + 5 : 45 = 9:05 pm It's pretty much it. In 1 hour and 45 minutes (7/4 hours) A traveled 7/4*60 = 105 miles. Distance to cover 455  105 = 350 miles. Combined rate (60 + 45) = 105 miles per hour, which mean that they will cover 350 miles in 350/105 = 10/3 hours (3 hours and 20 minutes). 5:45 pm + 3 hours and 20 minutes = 9:05 pm. Answer: C.
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Re: Train A and B, 455 miles apart, are traveling toward each ot
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26 Oct 2013, 07:48
We have: 455 = 60*1.75 + x*105. So we get x = (455105)/105= 10/3 = 3h 20mins. So the the answer should be 5:45 + 3:20=9:05 (C)



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Re: Train A and B, 455 miles apart, are traveling toward each ot
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31 Dec 2013, 12:09
fozzzy wrote: Train A and B, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train A left at 4 pm traveling at a speed of 60 miles per hour, and train B left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other? A. 7:20 pm B. 8:55 pm C. 9:05 pm D. 9:20 pm E. 9:25 pm Any faster approaches? train A travels for an hour and 45 mins so 7/4. distance travelled = 7/4 * 60 = 105.
since they track is 455 miles and Train A has travelled 105 miles. Now 350 miles left.
Since when they meet distance would be equal so 60t + 45t = 350
t = 10/3 so its 3 hours and 20 mins + 5 : 45 = 9:05 pm Nice problem, here we go First, since A has a headstart then in that 1hr45min or 1.75hrs he travels 105 miles Then remaining distance to be traveled will be 455  105 = 350 miles Now, using relative rates (105)(t) = 350 This gives 10/3 hours Now 5.45pm + 10/3 hours gives us 9.05pm Hence answer is C Hope it helps! Cheers! J



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Re: Train A and B, 455 miles apart, are traveling toward each ot
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08 Jan 2014, 09:04
Why is this different from the way that you are solving it?
D1= D2 then 60T = 45( T + 1.45h)
Once we know the time we could add it up to the starting time to know when is the meeting time i think.
Thank you very much in advance,



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Re: Train A and B, 455 miles apart, are traveling toward each ot
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10 Jan 2014, 03:57
guimooow wrote: Why is this different from the way that you are solving it?
D1= D2 then 60T = 45( T + 1.45h)
Once we know the time we could add it up to the starting time to know when is the meeting time i think.
Thank you very much in advance, What is T in your equation? Which distances are you equating? If you want to solve for T it should be: 60T + 45(T7/4) = 455, where T is the total time for A. Though it's much better to solve with step by step approach explained here: trainaandb455milesapartaretravelingtowardeachot161174.html#p1275213
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Re: Train A and B, 455 miles apart, are traveling toward each ot
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02 Mar 2016, 19:22
fozzzy wrote: Train A and B, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train A left at 4 pm traveling at a speed of 60 miles per hour, and train B left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other?
A. 7:20 pm B. 8:55 pm C. 9:05 pm D. 9:20 pm E. 9:25 pm
i tried to visualize it... so train A leaves at 4PM. at 5, 60 of the distance would be covered. distance between trains = 395. in another 45 mins, the train would travel another 45 miles. distance between them = 350. train B starts...now the distance between them would shrink by 60+45 or 105 miles per hour. 350/105 = 10/3. so additional 3 hours and 20 minutes after train B starts: 9:05PM



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Re: Train A and B, 455 miles apart, are traveling toward each ot
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15 Dec 2018, 05:30
In 1 hour and 45 minutes A will travel 7/4*60 = 105 miles. Remaining Distance to cover 455  105 = 350 miles. Combined speed of both the trains (60 + 45) = 105 mph They will cover 350 miles in 350/105 = 10/3 hours (3 hours and 20 minutes). So, 5:45 + 3 hours and 20 minutes = 9:05 pm. Hence, C.



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Re: Train A and B, 455 miles apart, are traveling toward each ot
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02 Oct 2019, 18:50
given distance 455 miles so at 4pm to 5:45 PM ; we have 1 hr 45 mins ; 105mins distance covered by A ; 60*105/60 ; 105 miles so both A &B start common at 350 miles relative speed ; 60+45 ; 105 mph time when they meet ; 350/105 ; 3.33hrs or say 3 hrs +.33*60 ; 3 hrs 20 mins from 5:45 PM i.e 9:05 PM IMO C fozzzy wrote: Train A and B, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train A left at 4 pm traveling at a speed of 60 miles per hour, and train B left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other? A. 7:20 pm B. 8:55 pm C. 9:05 pm D. 9:20 pm E. 9:25 pm Any faster approaches? train A travels for an hour and 45 mins so 7/4. distance travelled = 7/4 * 60 = 105.
since they track is 455 miles and Train A has travelled 105 miles. Now 350 miles left.
Since when they meet distance would be equal so 60t + 45t = 350
t = 10/3 so its 3 hours and 20 mins + 5 : 45 = 9:05 pm




Re: Train A and B, 455 miles apart, are traveling toward each ot
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02 Oct 2019, 18:50






