GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 21 Nov 2018, 08:08

# LBS is Calling R1 Admits - Join Chat Room to Catch the Latest Action

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
• ### All GMAT Club Tests are Free and open on November 22nd in celebration of Thanksgiving Day!

November 22, 2018

November 22, 2018

10:00 PM PST

11:00 PM PST

Mark your calendars - All GMAT Club Tests are free and open November 22nd to celebrate Thanksgiving Day! Access will be available from 0:01 AM to 11:59 PM, Pacific Time (USA)
• ### Key Strategies to Master GMAT SC

November 24, 2018

November 24, 2018

07:00 AM PST

09:00 AM PST

Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.

# Train T leaves town A for town B and travels at a constant rate of spe

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 50730
Train T leaves town A for town B and travels at a constant rate of spe  [#permalink]

### Show Tags

17 Oct 2017, 07:14
00:00

Difficulty:

35% (medium)

Question Stats:

73% (00:54) correct 27% (00:52) wrong based on 147 sessions

### HideShow timer Statistics

Train T leaves town A for town B and travels at a constant rate of speed. At the same time, train S leaves town B for town A and also travels at a constant rate of speed. Town C is between A and B. Which train is traveling faster? Towns A, C, and B lie on a straight line.

(1) Train S arrives at town C before train T.
(2) C is closer to A than to B.

_________________
PS Forum Moderator
Joined: 25 Feb 2013
Posts: 1217
Location: India
GPA: 3.82
Train T leaves town A for town B and travels at a constant rate of spe  [#permalink]

### Show Tags

17 Oct 2017, 11:09
1
Bunuel wrote:
Train T leaves town A for town B and travels at a constant rate of speed. At the same time, train S leaves town B for town A and also travels at a constant rate of speed. Town C is between A and B. Which train is traveling faster? Towns A, C, and B lie on a straight line.

(1) Train S arrives at town C before train T.
(2) C is closer to A than to B.

Let the speed of train T be $$u$$, time taken to reach C be $$t_1$$ and distance between A & C be $$x$$

Let the speed of train S be $$v$$, time taken to reach C be $$t_2$$ and distance between B & C be $$y$$

we need to find which speed between $$u$$ & $$v$$ is greatest

Statement 1: implies $$t_2<t_1$$ $$=> \frac{y}{v}<\frac{x}{u}$$

or $$u<\frac{x}{y}v$$. Now we need to know the ratio of $$\frac{x}{y}$$ to determine whether $$u$$ or $$v$$ is greater. But the value of $$x$$ & $$y$$ is not given. Hence Insufficient

Statement 2: implies that $$x<y => ut_1<vt_2$$. but nothing given about $$u$$, $$v$$ or $$t_1$$ & $$t_2$$. Hence Insufficient

Combining 1 & 2 we get $$x<y => \frac{x}{y}<1$$, multiply both sides by $$v$$ to get $$\frac{x}{y}v<v$$

from statement 1 we get $$u<v$$. Hence sufficient

Option C
Manager
Joined: 09 Aug 2017
Posts: 62
Location: United States
Concentration: Technology
GMAT 1: 640 Q44 V33
GMAT 2: 630 Q47 V29
WE: Research (Investment Banking)
Re: Train T leaves town A for town B and travels at a constant rate of spe  [#permalink]

### Show Tags

23 Oct 2017, 09:35
C, I had to do this one visually. So I drew a line with points A and B at each end. I drew T over point A and drew S over point B. I drew a point C halfway in between A and B, but I reminded myself that C could be anywhere between A and B.

St 1, says train S arrives at C before train T. Insufficient, but if we need the location of point C in relation to A and B, then that would suffice.
St 2, says point C is closer to point A.
-Insufficient by itself, but nevertheless, I crossed out where I had drawn C and moved it closer to A.

1+2, Since C is closer to point A and train S which is travelling a farther distance beats train T, then it must be the faster train.
_________________

I'd love to hear any feedback or ways to improve my problem solving. I make a lot of silly mistakes. If you've had luck improving on stupid mistakes, I'd love to hear how you did it.

Also, I appreciate any kudos.

Non-Human User
Joined: 09 Sep 2013
Posts: 8870
Re: Train T leaves town A for town B and travels at a constant rate of spe  [#permalink]

### Show Tags

23 Oct 2018, 20:15
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Train T leaves town A for town B and travels at a constant rate of spe &nbs [#permalink] 23 Oct 2018, 20:15
Display posts from previous: Sort by