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# triangle

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Manager
Joined: 16 Apr 2009
Posts: 213
Schools: Ross

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14 Jul 2009, 14:16
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If ABCD is a rectangle and E is the midpoint of side AD, BC is 12 and the area of the rectangle is 48, what is the area of triangle ACE?
24

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Senior Manager
Joined: 25 Mar 2009
Posts: 290

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14 Jul 2009, 14:20
I am calculating 12, not 24. This is also difficult to explain without a picture.
Manager
Joined: 16 Apr 2009
Posts: 213
Schools: Ross

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14 Jul 2009, 14:23
I also got 12. I got all these problems from www.bellcurves.com
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Senior Manager
Joined: 04 Jun 2008
Posts: 279

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14 Jul 2009, 14:32
12

AE = 6

Area = 48, thus AB = CD = 48/12 = 4

Area of triangle = base*height/2

if you imagine/draw ACE, and take AE as the base, then AB is the height of this triangle.

thus 6*4/2 = 12

24 cannot be. if 48 is total area of rectangle, then area of triangle ACB itself is 24,

Area of ACD = areaAEC + areaDCE = 24

AEC cannot be 24 anyway.
Current Student
Joined: 13 Jan 2009
Posts: 343
Location: India

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14 Jul 2009, 16:37
Area of triangle AEC=1/2*BC* height

Height=48/.5*12 ie 8

Now since AD is parallel to BC so AD=12 and since E is mid point so AE=6

Now Area of AEC=1/2*base*height
=1/2*6*8=24
Manager
Joined: 17 Dec 2007
Posts: 97

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14 Jul 2009, 17:50
1
hemantsood wrote:
Area of triangle AEC=1/2*BC* height

Height=48/.5*12 ie 8

Now since AD is parallel to BC so AD=12 and since E is mid point so AE=6

Now Area of AEC=1/2*base*height
=1/2*6*8=24

Hi

24 may not be the answer

a rectangle can be bisected by the diagonal to form two right angle triangle of equal area, if AC bisects the rectangle , then area of ABC is 24 and Area of ACD is 24 ( sums to 48). AE is a midpoint of AD which means base of triangle ACD is halfed and hence area is halfed.

make any sense
Current Student
Joined: 13 Jan 2009
Posts: 343
Location: India

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14 Jul 2009, 20:06
alwynjoseph wrote:
hemantsood wrote:
Area of triangle AEC=1/2*BC* height

Height=48/.5*12 ie 8

Now since AD is parallel to BC so AD=12 and since E is mid point so AE=6

Now Area of AEC=1/2*base*height
=1/2*6*8=24

Hi

24 may not be the answer

a rectangle can be bisected by the diagonal to form two right angle triangle of equal area, if AC bisects the rectangle , then area of ABC is 24 and Area of ACD is 24 ( sums to 48). AE is a midpoint of AD which means base of triangle ACD is halfed and hence area is halfed.

make any sense

My bad I read it as area of triangle BCE as 48.
Manager
Joined: 16 Apr 2009
Posts: 213
Schools: Ross

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15 Jul 2009, 18:53

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Keep trying no matter how hard it seems, it will get easier.

Re: triangle   [#permalink] 15 Jul 2009, 18:53
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