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Triangle T

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Manager
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Triangle T [#permalink]

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New post 09 Jun 2009, 07:30
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I don't understand what the 1st sentence is saying.
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Re: Triangle T [#permalink]

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New post 09 Jun 2009, 09:50
I will give it a try...first let me explain what is being asked in the question. The question tells you that there is a triangle lets say triangle KLM with a center T is in the xy-plane. Lets say, the three vertices of the triangle have vertices K(x1,y1), L(x2,y2) and M(x3,y3). It also says that the center is at T(x4, y4).

To see what a triangle in an xy-plane means see the attached image. Please remember the image is just an example I found online and not the solution to this question.

Now the question tells you that the x-coordinate (x4) of the center T = (x1+x2+x3)/3 (i.e. the average of the x-coordinates of the three vertices)
It also tells you that the y-coordinate (y4) of the center T = (y1+y2+y3)/3 (i.e. the average of the y-coordinates of the three vertices)

Now it gives us the values of the x and the y coordinates of two of the vertices and the center and asks us to find the x,y coordinates of the third one.

For x-coordinate 3 = (0+6+x3)/3 => x3=3
For y-coordinate 2=(0+0+y3)/3 => y3=6

The answer is (3,6)
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Re: Triangle T [#permalink]

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New post 09 Jun 2009, 10:11
thats correct explanation above.

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Re: Triangle T [#permalink]

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New post 10 Jun 2009, 21:16
Perfect calculation. (3,6)

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Re: Triangle T [#permalink]

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New post 13 Jun 2009, 01:37
nookway wrote:
I will give it a try...first let me explain what is being asked in the question. The question tells you that there is a triangle lets say triangle KLM with a center T is in the xy-plane. Lets say, the three vertices of the triangle have vertices K(x1,y1), L(x2,y2) and M(x3,y3). It also says that the center is at T(x4, y4).

To see what a triangle in an xy-plane means see the attached image. Please remember the image is just an example I found online and not the solution to this question.

Now the question tells you that the x-coordinate (x4) of the center T = (x1+x2+x3)/3 (i.e. the average of the x-coordinates of the three vertices)
It also tells you that the y-coordinate (y4) of the center T = (y1+y2+y3)/3 (i.e. the average of the y-coordinates of the three vertices)

Now it gives us the values of the x and the y coordinates of two of the vertices and the center and asks us to find the x,y coordinates of the third one.

For x-coordinate 3 = (0+6+x3)/3 => x3=3
For y-coordinate 2=(0+0+y3)/3 => y3=6

The answer is (3,6)


Thanks Nookway, you're a gem! I tried visualizing without drawing on draft. Your explanation is clear.

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Re: Triangle T   [#permalink] 13 Jun 2009, 01:37
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