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Q- In the junior basketball league there are 18 teams, 2/3 of them are bad and 1/2 are rich. What can't be the number of teams that are rich and bad?
a)4 b)6 c) 10 d)13 e)15
The Answer is (C)
The given explanation is :
12 teams are bad and 9 are rich.
The no. of teams which are rich and that are bad must be between 9 and (9+12-18=3)
The only answer, which is not in that range is (C)
I did not understand this explanation. Please help me !! Thanks in advance.
a)4 b)6 c) 10 d)13 e)15
The Answer is (C)
The given explanation is :
12 teams are bad and 9 are rich.
The no. of teams which are rich and that are bad must be between 9 and (9+12-18=3)
The only answer, which is not in that range is (C)
I did not understand this explanation. Please help me !! Thanks in advance.
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13 Feb 2011, 03:32
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They can be both bad and rich.
Think of it as a Venn-diagram, left circle bad and right circle rich.
If 10 are both bad and rich, that implies that at least 10 are bad, but only 9 are bad so it cannot be true.
Think of it as a Venn-diagram, left circle bad and right circle rich.
If 10 are both bad and rich, that implies that at least 10 are bad, but only 9 are bad so it cannot be true.
13 Feb 2011, 03:58
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Moved to PS subforum.
How can the number of teams that are BOTH rich and bad be more than the teams that are rich (9)? So 9 is the upper limit for the number of teams that are BOTH rich and bad. The lower limit for the the number of teams that are BOTH rich and bad is 3: TOTAL=Bad+Rich-Both+Neither --> 18=12+9-Both+Neither --> Both=3+Neither, so if there are no teams that are neither bad or rich then Both=3.
So there are 3 values among answer choices which can't be the number of teams that are both rich and bad: C, D, and E.
P.S.
sandhyash
How can the number of teams that are BOTH rich and bad be more than the teams that are rich (9)? So 9 is the upper limit for the number of teams that are BOTH rich and bad. The lower limit for the the number of teams that are BOTH rich and bad is 3: TOTAL=Bad+Rich-Both+Neither --> 18=12+9-Both+Neither --> Both=3+Neither, so if there are no teams that are neither bad or rich then Both=3.
So there are 3 values among answer choices which can't be the number of teams that are both rich and bad: C, D, and E.
P.S.
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