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Trucks A, B, and C, working together, can move a load of sand in "t" h
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Bunuel
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Trucks A, B, and C, working together, can move a load of sand in "t" h [#permalink] New post  08 Feb 2021, 01:02
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Trucks A, B, and C, working together, can move a load of sand in "t" hours. When working alone, it takes truck A one extra hour to move the sand; B, six extra hours; and C, "t" extra hours. What is the value of t?

A. 1/6
B. 1/4
C. 1/3
D. 2/3
E. 3/4
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sthahvi
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Re: Trucks A, B, and C, working together, can move a load of sand in "t" h [#permalink] New post  14 Feb 2021, 03:43
what is wrong with this method:
1/a= t+1, 1/b=t+6, 1/c=2t
1/a+1/b+1/c=t
substitute values as mentioned above then we get:
t+1 + t+6+ 2t = t
what is wrong with this ?
why am I not getting the answer ?
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DudeBeCool
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Trucks A, B, and C, working together, can move a load of sand in "t" h [#permalink] New post  18 Feb 2021, 09:56
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Time taken by A = t+1
Time taken by B = t+6
Time taken by C = 2t

Adding in the equation, R*T = W, we get

[1/A + 1/B + 1/C] * t = 1

solve for 't' and you will get your answer.

Answer: 2/3
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jrk23
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Re: Trucks A, B, and C, working together, can move a load of sand in "t" h [#permalink] New post  24 Feb 2021, 06:26
Bunuel wrote:
Trucks A, B, and C, working together, can move a load of sand in "t" hours. When working alone, it takes truck A one extra hour to move the sand; B, six extra hours; and C, "t" extra hours. What is the value of t?

A. 1/6
B. 1/4
C. 1/3
D. 2/3
E. 3/4


One more solution :

as per question:

1/(t+1) + 1/(t+6) + 1/2t= 1/t

= 1/(t+1) + 1/(t+6) = 1/2t

= 3t^2-7t-6=0
=t is -3,2/3

t can't be negative so t=2/3
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Brian123
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Re: Trucks A, B, and C, working together, can move a load of sand in "t" h [#permalink] New post  24 Feb 2021, 20:16
sthahvi wrote:
what is wrong with this method:
1/a= t+1, 1/b=t+6, 1/c=2t
1/a+1/b+1/c=t
substitute values as mentioned above then we get:
t+1 + t+6+ 2t = t
what is wrong with this ?
why am I not getting the answer ?


sthahvi, the highlighted portion is wrong. You've taken t+1,t+6 and 2t to be the rates of A,b,c. That is the total time. A=t+1, b=t+6 and c=2t.

Hence,
1/a=1/t+1
1/b=1/t+6
1/c=1/2t.
1/a +1/b +1/c = t.

^solve the above for t and you'll get your answer!
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