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Trucks A, B, and C, working together, can move a load of sand in "t" h
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08 Feb 2021, 01:02
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Question Stats:
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correct 48%
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Trucks A, B, and C, working together, can move a load of sand in "t" hours. When working alone, it takes truck A one extra hour to move the sand; B, six extra hours; and C, "t" extra hours. What is the value of t?
Re: Trucks A, B, and C, working together, can move a load of sand in "t" h
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14 Feb 2021, 03:43
what is wrong with this method: 1/a= t+1, 1/b=t+6, 1/c=2t 1/a+1/b+1/c=t substitute values as mentioned above then we get: t+1 + t+6+ 2t = t what is wrong with this ? why am I not getting the answer ?
Re: Trucks A, B, and C, working together, can move a load of sand in "t" h
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24 Feb 2021, 06:26
Bunuel wrote:
Trucks A, B, and C, working together, can move a load of sand in "t" hours. When working alone, it takes truck A one extra hour to move the sand; B, six extra hours; and C, "t" extra hours. What is the value of t?
Re: Trucks A, B, and C, working together, can move a load of sand in "t" h
[#permalink]
24 Feb 2021, 20:16
sthahvi wrote:
what is wrong with this method: 1/a= t+1, 1/b=t+6, 1/c=2t 1/a+1/b+1/c=t substitute values as mentioned above then we get: t+1 + t+6+ 2t = t what is wrong with this ? why am I not getting the answer ?
sthahvi, the highlighted portion is wrong. You've taken t+1,t+6 and 2t to be the rates of A,b,c. That is the total time. A=t+1, b=t+6 and c=2t.
Hence, 1/a=1/t+1 1/b=1/t+6 1/c=1/2t. 1/a +1/b +1/c = t.
^solve the above for t and you'll get your answer!
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