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03 Jun 2025, 00:30
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
64% (01:04) correct
36%
(01:09)
wrong
based on 154
sessions
History
Date
Time
Result
Not Attempted Yet
Two coins are loaded so that each comes up heads 60% of the time when tossed. If the coins are both tossed at the same time, what is the probability that the result will be one head and one tail?
(A) 0.52
(B) 0.5
(C) 0.6
(D) 0.24
(E) 0.48
Veritas Prep
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(A) 0.52
(B) 0.5
(C) 0.6
(D) 0.24
(E) 0.48
Veritas Prep
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
03 Jun 2025, 10:14
Kudos
Bookmarks
Bunuel
Probabilty of getting a Head = 60% = 60/100 = 3/5
Probability of getting a Tail = 1 - Probability of getting a Head = 1 - (3/5) = 2/5
Probability of getting one head and one tail = P(HT) or P(TH)
= P(HT) + P(TH)
= (3/5)*(2/5) + (2/5)*(3/5)
= (6/25) + (6/25)
= 12/25
= 0.48
Option E
03 Jun 2025, 10:34
Kudos
Bookmarks
P(H) = 0.6
P(T) = 0.4
P(HT) = P(TH) = 0.24
Probability that the result will be one head and one tail: First coin Head, Second coin Tail and First coin Tail, Second coin Head
P(HT) + P(TH) = 0.24 * 2 = 0.48
P(T) = 0.4
P(HT) = P(TH) = 0.24
Probability that the result will be one head and one tail: First coin Head, Second coin Tail and First coin Tail, Second coin Head
P(HT) + P(TH) = 0.24 * 2 = 0.48
Bunuel
