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26 Feb 2021, 06:00
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Two dice, each numbered 1 to 6, are tossed. What is the probability that the total score is 9 ?
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
26 Feb 2021, 06:49
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Bunuel
Two dice, each numbered 1 to 6, are tossed. What is the probability that the total score is 9 ?
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
P(sum is 9) = P(1st is 6 and 2nd is 3 OR 1st is 3 and 2nd is 6 OR 1st is 5 and 2nd is 4 OR 1st is 4 and 2nd is 5)
= P(1st is 6) x P(2nd is 3) + P(1st is 3) x P(2nd is 6) + P(1st is 5) x P(2nd is 4) + P(1st is 4) x P(2nd is 5)
= 1/6 x 1/6 + 1/6 x 1/6 + 1/6 x 1/6 + 1/6 x 1/6
= 1/36 + 1/36 + 1/36 + 1/36
= 4/36
= 1/9
Answer: B
06 Dec 2022, 14:53
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BrentGMATPrepNow
Bunuel
Two dice, each numbered 1 to 6, are tossed. What is the probability that the total score is 9 ?
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
A. 1/36
B. 1/9
C. 11/36
D. 25/36
E. 35/36
P(sum is 9) = P(1st is 6 and 2nd is 3 OR 1st is 3 and 2nd is 6 OR 1st is 5 and 2nd is 4 OR 1st is 4 and 2nd is 5)
= P(1st is 6) x P(2nd is 3) + P(1st is 3) x P(2nd is 6) + P(1st is 5) x P(2nd is 4) + P(1st is 4) x P(2nd is 5)
= 1/6 x 1/6 + 1/6 x 1/6 + 1/6 x 1/6 + 1/6 x 1/6
= 1/36 + 1/36 + 1/36 + 1/36
= 4/36
= 1/9
Answer: B
Hi Brent BrentGMATPrepNow, is below reasoning correct?
Two dice, total number of outcomes is 36
Among the numbers 1,2,3,4,5,6, there are only 4 numbers add up to 9.
Therefore 4/36 = 1/9
