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Two jugs, J and K , contain water. The capacity of jug J is 20 percent

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Two jugs, J and K , contain water. The capacity of jug J is 20 percent  [#permalink]

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New post 16 Apr 2018, 08:07
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C
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Difficulty:

  55% (hard)

Question Stats:

56% (01:19) correct 44% (01:29) wrong based on 50 sessions

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Two jugs, J and K , contain water. The capacity of jug J is 20 percent greater than that of jug K . How many more gallons of water are in jug J than in jug K ?

1) When full, jug K holds 5 gallons of water.
2) Jug J is 50 percent full and jug K is 40 percent full.

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Re: Two jugs, J and K , contain water. The capacity of jug J is 20 percent  [#permalink]

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New post 18 Apr 2018, 22:47
itisSheldon wrote:
Two jugs, J and K , contain water. The capacity of jug J is 20 percent greater than that of jug K . How many more gallons of water are in jug J than in jug K ?

1) When full, jug K holds 5 gallons of water.
2) Jug J is 50 percent full and jug K is 40 percent full.


So the two jugs have certain individual capacities, but they are not necessarily filled to capacity.

(1) Capacity of K is 5 gallons, and this means capacity of J should be 20% more or 6 gallons. So now we have their capacities but no idea how much of them are filled. So not sufficient.

(2) Lets say capacity of K is x gallons, this means capacity of J will be 1.2x gallons (20% more than K). Given water in jug J = 50% of capacity = 0.5*1.2x = 0.6x gallons, while Water in jug K = 0.4x. The difference = 0.6x - 0.4x = 0.2x gallons. But since we dont have the value of x, we cant answer in terms of gallons of water. Not sufficient.

Combining the statements, we have the value of x as 5 and 1.2x as 6. So water in jug J = 3 gallons while water in jug K = 2 gallons. Difference = 1 gallon. Sufficient.

Hence C answer
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Re: Two jugs, J and K , contain water. The capacity of jug J is 20 percent  [#permalink]

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New post 30 Apr 2018, 10:02
J=1.2K

I) k capacity=5
J capacity=1.2*5=6
But we don't know how much they're filled

II)don't know capacity of J and K

Combining both
J=6 K=5
Currently J has 6/2=3
K has (2/5)*5=2

So J has 3-2=1 gallon more than K

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Re: Two jugs, J and K , contain water. The capacity of jug J is 20 percent &nbs [#permalink] 30 Apr 2018, 10:02
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