From the question stem one gets: \(l = 0.5e + 10\). From this, one can see that firstly, Essien must have an equal number of chocolates and secondly, if he has more than 20 chocolates it will have to be an even number greater than 21.
If Essien has over 20 chocolates, the minimum he will have is 22 chocolates. If he does, then Lampard will have 21.
(1) The difference between the number of chocolates than Lampard and Essien had was less than 30.From the above, if Essien has 22 chocolates and Lampard has 21, then the difference will be 1 which holds with the above statement.
If Essien has 10 chocolates, then Lampard has 15. Here the difference is 5 which holds with the statement above.
Without further information it is impossible to solve for the question.
INSUFFICIENT(2) The total number of chocolates than Lampard and Essien had was greater than 5/2 of the number of the chocolates with Essien.Translating this into an equation: \(l + e > \frac{5}{2}e\)
PLUGGING IN \(l = 0.5e + 10\)
INTO THE ABOVE: \(0.5e + 10 + e > \frac{5}{2}e\)
\(10 > e\)
SUFFICIENT
ANSWER B