Two sets, A and B, have the same number of elements and the same median. Which set has the higher average?
(1) In Set A, 75% of the numbers are greater than or equal to the median. In Set B, 50% of the numbers are greater than or equal to the median.
The above question is from
MGMAT flashcard of word translation section.
The question is for revision purpose and statement 2 is not given,
The above statement is insufficient to answer a question.
i dint understood an explanation given in flashcard.
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Just think about the question. What is the median ? If you arrange the number in ascending or descending order than the middle number gives the median.
Statement A says 75% of the numbers are greater than or equal too to the median. This means 3/4 of the numbers are equal to the median. Their is no way that 75% can be > the median because than that number is not the median. So this set is something like :
{4,5,5,5} -> median is 5 or {-1,2,2,10} median is 2.
Now Set B is something
Set B
2,4,6,10 -> median is 5 same as above or {0,1,3,4} - median is 2.
Now Avg in set B is greater than Avg in Set A. However Avg in Set A > Avg in set B for the 2nd case.
Hence, one cannot determine whose average is more than the other.