Two sets, A and B, include only positive integers. If set A and set B

Since the sets have an equal number of terms, Statement 2 tells us they have the same average, so we just want to know if A's median is bigger than A's average. But we have no information about that anywhere in the question - the fact from Statement 1 that A contains even terms is irrelevant. If A is symmetric, its mean and median will be equal; if its elements are skewed so they are mostly small, its median will be smaller than its mean, and if it is skewed so most of its elements are large, its median will exceed its mean. So the answer is E.

If one wanted examples here, one where A's median exceeds B's mean (and thus of A's mean), and one where A's median is less than B's mean, we could have, with a sum of 300 for each set (so a mean of 75 for each) :

A = 0, 98, 100, 102
B = -1, 1, 149, 151

where A has a larger median than mean, or we could have

A = 0, 2, 4, 294
B = -1, 1, 149, 151

where A has a smaller median than mean.

A "set" in math does not contain repeated elements, so the solution posted above mine is technically incorrect.