|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
17 Oct 2020, 00:41
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
80% (03:18) correct
20%
(03:06)
wrong
based on 87
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
2.jpg [ 17.02 KiB | Viewed 3035 times ]
Two square rugs, R and S, have a combined area of 20 square feet and are placed on a floor whose area is 112 square feet, as shown above. Measured east to west, each rug is placed the same distance from the other rug as from the nearest east or west edge of the floor. If the area of rug R is four times the area of rug S, how far apart are the rugs?
(A) 1 foot, 6 inches
(B) 2 feet
(C) 2 feet, 8 inches
(D) 3 feet
(E) 3 feet, 4 inches
17 Oct 2020, 04:31
Kudos
Bookmarks
Sajjad1994
R + S = 20 and R = 4S
Substituting for R, we get 4S + S = 20
5S = 20
Area of S = 4 square feet (side length = 2) and
Area of R = 20 - 4 = 16 square feet (side length = 4)
Area of the floor = 112 square feet and it's breadth is 8 feet.
The length = \(\frac{112}{8}\) = 14 feet
Now, this length of 14 feet has 4 feet of square R and 2 feet of square S. The remaining length = 14 - 4 - 2 = 8 feet
This 8 feet is divided equally into 3 distances (one end of floor to R, R to S and S to the other end)
Therefore the distance = \(\frac{8}{3} = 2 \frac{2}{3}\) = 2 feet, 8 inches (12 inches = 1 foot)
Option C
Arun Kumar
