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08 Dec 2021, 04:15
Kudos
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C
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Difficulty:
65%
(hard)
Question Stats:
56% (01:34) correct
44%
(01:30)
wrong
based on 233
sessions
History
Date
Time
Result
Not Attempted Yet
Two taps with emptying capacities in the ratio 1 : 2, empty a full tank in 2 hours when opened together. How much time does the first tap alone take to empty half the tank?
(A) 1.5 hours
(B) 2 hours
(C) 3 hours
(D) 6 hours
(E) 8 hours
Are You Up For the Challenge: 700 Level Questions
(A) 1.5 hours
(B) 2 hours
(C) 3 hours
(D) 6 hours
(E) 8 hours
Are You Up For the Challenge: 700 Level Questions
08 Dec 2021, 05:40
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Bunuel
Let the first tap empty 10 litres in one hour so the second tap does 20 litres in 1hour.
Together they empty 30 litres in an hour. So in two hours they would drain 60 litres.
Now question is asking about the half of the capacity that is 30litres.
So time taken by first tap will be 30/10 = 3hours. C
General Discussion
25 Feb 2023, 10:58
Kudos
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Time = Work / Rate.
A is the rate of the first pipe and hence 0.5A that of the second.
A + 0.5A = 1.5A
Hence 1/1.5A = 2 => 3A = 1 => A = 1/3.
The time for the first pipe is 1/(1/3) = 3 Hours.
A is the rate of the first pipe and hence 0.5A that of the second.
A + 0.5A = 1.5A
Hence 1/1.5A = 2 => 3A = 1 => A = 1/3.
The time for the first pipe is 1/(1/3) = 3 Hours.
