Bunuel
Two types of tea, A and B, are mixed and then sold at $40 per kg. The profit is 10% if A and B are mixed in the ratio 3 : 2, and 5% if this ratio is 2 : 3. The cost prices, per kg, of A and B are in the ratio
A. 21 : 25
B. 19 : 24
C. 18 : 25
D. 17 : 25
E. 13 : 25
Let the Cost price of tea A & B be '\(a\)' & '\(b\)' respectively
The profit is 10% if A and B are mixed in the ratio 3 : 2
--> Fraction of tea A & B = \(\frac{3a}{5}\) & \(\frac{2b}{5}\)
Also, SP = 110% of CP
--> \(40 = \frac{110}{100}*\frac{(3a + 2b)}{5}\) ....... (1)
The profit is 5% if A and B are mixed in the ratio 2 : 3
--> Fraction of tea A & B = \(\frac{2a}{5}\) & \(\frac{3b}{5}\)
SP = 105% of CP
--> \(40 = \frac{105}{100}*\frac{(2a + 3b)}{5}\) ....... (2)
From (1) & (2),
\(\frac{110}{100}*\frac{(3a + 2b)}{5} = \frac{105}{100}*\frac{(2a + 3b)}{5}\)
--> \(110(3a + 2b) = 105(2a + 3b)\)
--> \(22(3a + 2b) = 21(2a + 3b)\)
--> \(66a + 44b = 42a + 63b\)
--> \(24a = 19b\)
-->\(\frac{a}{b} = \frac{19}{24}\)
Option B