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Two watermelons of the same sort, A and B, are on sale. [#permalink]

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30 Oct 2008, 06:15

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Two watermelons of the same sort, A and B, are on sale. Watermelon A has circumference of 60 cm, watermelon B, of 50 cm. If the price of watermelon A is 1.5 times the price of watermelon B, which watermelon is a better buy?

(You may assume that the watermelon is spherical in shape)

* A * B * Either * Neither * Impossible to determine

I think A is the best buy as the volume of the watermelon is important. The volume is 4/3pi*r^3 so the radius of watermelon A= 30/pi watermelon B=25/pi So keeping the 4/3 and pi constant the ratio of volume is 30*30*30/25*25*25=1.7 But the price of A is 1.5 times of B where as the volume of A is 1.7 times of B. So I think A is the best buy

I think A is the best buy as the volume of the watermelon is important. The volume is 4/3pi*r^3 so the radius of watermelon A= 30/pi watermelon B=25/pi So keeping the 4/3 and pi constant the ratio of volume is 30*30*30/25*25*25=1.7 But the price of A is 1.5 times of B where as the volume of A is 1.7 times of B. So I think A is the best buy

What is the OA??

Definitely we need to consider weight not area or redius/diameter or circumference.
_________________

Will it be considered that the watermelon with greater volume will be of greater weight? (well, then we have to assume the densities of the both watermelon are same). If not then, the condition is not sufficient enough.
_________________

A's volume is about 1.7 times bigger than B's, therefore A is a better buy. But... every time I come up with smth like that the answer is E, because... watermellon A can be rotten inside and from info above it is impossible to determine.