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V1, V2 are two rectangular tanks. Is total surface area of V1 < V2?

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V1, V2 are two rectangular tanks. Is total surface area of V1 < V2? [#permalink]

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New post 14 Mar 2018, 23:36
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A
B
C
D
E

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Question Stats:

26% (00:21) correct 74% (00:26) wrong based on 19 sessions

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V1 and V2 are two rectangular tanks. Is the total surface area of V1 less than that of V2?

(1) Height of V1 is same as that of V2.

(2) V1 has a square base. Area of base of V1 is same as that of V2.
[Reveal] Spoiler: OA
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Re: V1, V2 are two rectangular tanks. Is total surface area of V1 < V2? [#permalink]

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New post 15 Mar 2018, 02:51
amanvermagmat wrote:
V1 and V2 are two rectangular tanks. Is the total surface area of V1 less than that of V2?

(1) Height of V1 is same as that of V2.

(2) V1 has a square base. Area of base of V1 is same as that of V2.


To know the surface area, we need to know the areas of the 6 sides.
We'll look for statements that give us this information, a Logical appraoch.

(1) What are the areas?
Insufficient.

(2) What about the areas of the sides?
Insufficient.

Combined:
2 tells us the base and top have the same area.
The area of the sides is the height*length or height*width.
If V2 is also a square than V1 and V2 have identical length,width so identical surface area and the answer is NO.
Let's try making the answer a YES.
Say V1 has a height is 1 and the area of the base is 1.
Then V1 is a 1*1*1 cube and each side has an area of 1 so 4 sides have an area of 4..
We'll push V2 to the extreme: say its width, length are 1000 and 1/1000 (which gives an area of 1).
Then one of its sides has an area of 1000*1 which is certainly larger than 4.
In this case, V2 has a larger surface area. That is, the answer is YES.
Insufficient.

(E) is our answer.
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Re: V1, V2 are two rectangular tanks. Is total surface area of V1 < V2?   [#permalink] 15 Mar 2018, 02:51
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V1, V2 are two rectangular tanks. Is total surface area of V1 < V2?

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