bagdbmba
Hi Karishma,
Could you please confirm this -
OA of Qs #2 of your
blog post should be A (and the total ways would be \(7C5*4!\) ).
Look forward to your feedback!
Answer is actually (C)
Two cases:
7 children, 5 chairs in a circle:
Select 5 out of 7 children in 7C5 ways. Arrange 5 children in 5 chairs in a circle in 4! ways.
Total arrangements: 7C5 * 4!
5 children, 7 chairs in a circle:
If you have 7 distinct objects, then you can choose 2 in 7C2 ways. But here, the chairs arranged in a circle are identical initially. Say you choose two chairs to discard. They are right next to each other, how are they any different from any other two chairs right next to each other?
When you have 5 children and 7 chairs in a circle, you place the first child on any chair in 1 way.
Then you have 4 children and 6 distinct chairs. You can place the 4 children in 6*5*4*3 ways.
Total number of ways of placing 5 children in 7 chairs in a circle = 6*5*4*3
Depending on what is 7 and what is 5, your answer changes.