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niheil
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Thanks shrouded1 and Bunuel! Your answers are very helpful. I'll look into permutations and combinations.
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let assume there are 3 seats and we have 5 people

so for the 1st seat number of options, we have = 5

for the 2nd seat = 4 ( one is already on the 1st seat)
for the 3rd seat = 3 ( two are already on 1st and 2nd)

so total option on 3 seats = 5*4*3 =60 ( we don't need to do the math)
but the question is asking about a group
so how many ways u can sort 3 people = 3! = 3x2 =6 ( so that means we can have 6 arrangements in which we can arrange 3 people )

so \(Total_Groups = \frac{Total Seat Arrangements}{No Of Arragements Per Group} = \frac{60}{6} = 10\)
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