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E
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Difficulty:
5%
(low)
Question Stats:
87% (01:21) correct
13%
(01:32)
wrong
based on 276
sessions
History
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Joan has 100 candies to distribute among 10 children. If each child receives at least 1 candy and no two children receive the same number of candies, what is the maximum number of candies that a child can receive?
A. 10
B. 34
C. 39
D. 45
E. 55
A. 10
B. 34
C. 39
D. 45
E. 55
Updated on: 23 Oct 2025, 10:07
Originally posted by ankitranjan on 18 Oct 2010, 10:25.
Last edited by Bunuel on 23 Oct 2025, 10:07, edited 1 time in total.
Last edited by Bunuel on 23 Oct 2025, 10:07, edited 1 time in total.
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shrive555
No its not a combination question. It is somewhat tricky. Here we have to distribute 100 candies in 10 children and no two children will receive the same number of candy .so for making the number of candies maximum for one child we have to make it minimum for the remaining children i.e 1,2,3,4,5,6,7,8,9 so total will be 45 for 9 children.
For the tenth child who is getting maximum, the number of candies will be ( 100-45)=55.Hence answer is E
18 Oct 2010, 14:21
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shrive555
To maximize the number of candies a child gets, we will need to minimize the number that the other 9 get.
Child 1 : We give him 1 because thats the minimum we can give
Child 2 : We can't give 1 (since number has to be unique). So we give 2
Child 3 : We can't give 1 or 2, so we give 3
....
Child 9 : We can't give 1,2,3,..,8. So we give 9
So total distributed so far = 1+2+3+...+9 = 9(10)/2 =45
The rest we give to child 10, which is the maximum possible, and is 100-45 or 55.
Answer is (e)
