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This seems like an awkward question to me. The number favoring more than one proposal should include those who favor all three (since three is greater than one). This would be 80+30+20-78 = 22%. The fact that they provided the information that 5% favor all three proposals suggests to me that the intent of the question was to ask how many favor exactly two of the proposals.

Is this a GMAT question?
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This seems like an awkward question to me. The number favoring more than one proposal should include those who favor all three (since three is greater than one). This would be 80+30+20-78 = 22%. The fact that they provided the information that 5% favor all three proposals suggests to me that the intent of the question was to ask how many favor exactly two of the proposals.

Is this a GMAT question?

Those who favored more than one of the 3 proposals does include those who favored exactly 2 and all 3, but this group doesn't equal to 22%. It equals to \(\{favored \ exactly \ 2 \ proposals\}+\{favored \ exactly \ 3 \ proposals\}=12+5=17\).
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Bunuel, my answer for exactly 2 people was 17 and this was my approach:

100%=(A+B+C)-(AnB+AnC+BnC)-5%+22% which leads me to

100%=(50+30+20)-(at least 2 people)-5%+22%

when I add 5% to this to get at least more than one of the three proposals I get 22%. Where am I going wrong? why do you multiply by 2*(favored exactly 3 proposals)? Thanks.
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Bunuel, my answer for exactly 2 people was 17 and this was my approach:

100%=(A+B+C)-(AnB+AnC+BnC)-5%+22% which leads me to

100%=(50+30+20)-(at least 2 people)-5%+22%

when I add 5% to this to get at least more than one of the three proposals I get 22%. Where am I going wrong? why do you multiply by 2*(favored exactly 3 proposals)? Thanks.

Check this: formulae-for-3-overlapping-sets-69014.html#p729340
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Thanks Bunuel very helpful.
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total = I + II + III -2(all three) -(two proposals) + neither
100-neither = 50+30+20 -2(5) -y
78 = 90 - y
y = 12 ............... number of people who voted for two proposals

12+5= 17 .......... people who voted for 2 or 3 proposals
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cleetus
This is a simple question to answer. Just thought of posting it with solution.

In a survey of political preferences, 78% of those asked were in favour of at least one of the proposals:
I, II and III. 50% of those asked favoured proposal I, 30% favoured proposal II, and 20% favoured proposal III. If 5% of those asked favoured all three of the proposals, what percentage of those asked favoured more than one of the 3 proposals.
(A) 10 (B) 12 (C) 17 (D) 22 (E) 30

My solution -
5% of those asked favoured all three of the proposals. The statement does not say that the exactly 5% of the people favoured all three of the proposals. Hence we can apply following formula.

x = I n II + II n III + I n III
5 is I n II n III

78 = 50 + 30 + 20 - x + 5
x = 27. In this value of 27 the intersection between all three sets is counted 3 times so substract it two times i.e., substract 2 *5 = 10

Total folks in favour of two or more proposals = 27 - 10 = 17
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Hi Bunnel,
I get confused where to use the first formula and where to use the second formula . I there any way to identify where to use them ? I usually solve by using the Venn diagrams. So getting confused with the formulas

Thanks, .
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prashd
Hi Bunnel,
I get confused where to use the first formula and where to use the second formula . I there any way to identify where to use them ? I usually solve by using the Venn diagrams. So getting confused with the formulas

Thanks, .

This is explained here: advanced-overlapping-sets-problems-144260.html
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Total surveyed = (P1 + P2 + P3) - (# who liked exactly 2) - 2(Liked all three)
78 = (50 + 30 + 20) - x - 10
x = 12 <---Total # who like exactly 2

12 + 5 = 17 <----Total who like more than one.

Answer is C.
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