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16 Dec 2010, 01:40
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N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
67% (00:27) correct
33%
(04:01)
wrong
based on 12
sessions
History
Date
Time
Result
Not Attempted Yet
There are 12 co-workers who work on projects in teams each month. Each team is comprised of 3 people and every team is together only once before the rotation begins again. How many unique teams can be created?
My effort:
From the above scenario, it is clear that there are 4 teams and each comprises of 3 people.
Hence, i took m=4 and n=3 in the formula (mn)! / (n!)^m * m!
but the answer coming is wrong. Can somebody please tell me whats wrong in here?
OA : 220
My effort:
From the above scenario, it is clear that there are 4 teams and each comprises of 3 people.
Hence, i took m=4 and n=3 in the formula (mn)! / (n!)^m * m!
but the answer coming is wrong. Can somebody please tell me whats wrong in here?
OA : 220
16 Dec 2010, 02:10
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krishnasty
Hi!
You've vastly overcomplicated the problem.
The simplest interpretation of the question is "how many unique groups of 3 people can be made out of a total pool of 12?"
The answer is then 12C3. Plugging into the combinations formula:
12C3 = 12!/3!9! = 12*11*10/3*2*1 = 2*11*10 = 220
To be honest, I'm not even sure where they formula you used comes from - I've never seen it before.
16 Dec 2010, 04:16
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well, that seemed a very easy approach to do so..
The formula that i have used was posted by Bunuel in some of his post. And to tell you the truth, i have often used this formula to derive the correct answer..
@Bunuel, can you please point out if i used the formula incorrectly or where exactly i made a mistake.
Thanks Guys!!
The formula that i have used was posted by Bunuel in some of his post. And to tell you the truth, i have often used this formula to derive the correct answer..
@Bunuel, can you please point out if i used the formula incorrectly or where exactly i made a mistake.
Thanks Guys!!
. For the GMAT it's enough to remember just the basic formulas for combinations and permutations. If you understand these formulas and know how to apply them you should be able to answer pretty much all the questions. 
