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22 Dec 2010, 17:28
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
84% (00:45) correct
16%
(00:52)
wrong
based on 464
sessions
History
Date
Time
Result
Not Attempted Yet
If \(y\frac{3x-5}{2}=y\) and y is different from 0, then \(x=\)
A) \(\frac{2}{3}\)
B) \(\frac{5}{3}\)
C) \(\frac{7}{3}\)
D) 1
E) 4
Reasoning, see the spoiler part:
OPEN DISCUSSION OF THIS QUESTION IS HERE: if-y-3x-5-2-y-and-y-0-then-x-143491.html
A) \(\frac{2}{3}\)
B) \(\frac{5}{3}\)
C) \(\frac{7}{3}\)
D) 1
E) 4
Reasoning, see the spoiler part:
I got it wrong because when I did the calculation I swapped y on the right hand side to the left hand side to get \((3x-5)/2=0\) and then obviously I got the answer B rather than the OA C. I understand the OA however I would like to ask my silly question, which is why can I not do the way I did it. Is it wrong? It must be but WHY?
OPEN DISCUSSION OF THIS QUESTION IS HERE: if-y-3x-5-2-y-and-y-0-then-x-143491.html
whiplash2411
Joined: 09 Jun 2010
Last visit: 02 Mar 2015
Posts: 1,761
Given Kudos: 210
Status:Three Down.
Concentration: General Management, Nonprofit
Schools: HBS '17 (M) Stanford '17 (A)
22 Dec 2010, 17:39
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Burnkeal
\(y\frac{3x-5}{2}=y\)
\(y (\frac{3x-5}{2} -1) = 0\), and hence \(\frac{3x-5}{2} = 1\) and hence \(x = \frac{7}{3}\)
The mistake you made was equating it to zero. If you cancel y on both sides (which you can, since its not zero), the right hand side will be 1, not 0. Hope its clear.
