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28 May 2011, 07:54
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Difficulty:
55%
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Question Stats:
67% (02:10) correct
33%
(02:14)
wrong
based on 211
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In a country the total population is 50 million and they are distributed among 6 territories in descending order as follows, J,K,L,M,N,P where some territories can have the same amount of people. If M has 21% of the total population and P has 2 million people, what is the maximum amount of people (in millions) in territory N?
a) 4
b) 6
c) 8.5
d) 9
e) 10.5
a) 4
b) 6
c) 8.5
d) 9
e) 10.5
28 May 2011, 08:02
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\(J\ge K\ge L\ge M\ge N\ge P\)
N is maximum when J, K and L are minimum. It's possible when:
\(J= K= L=M\ge N\ge P\)
So,
4*21%*50 + N + 2 = 50
42 + N + 2 = 50
N = 6
N is maximum when J, K and L are minimum. It's possible when:
\(J= K= L=M\ge N\ge P\)
So,
4*21%*50 + N + 2 = 50
42 + N + 2 = 50
N = 6
30 May 2011, 04:00
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4* (21/100) * 50 * 10^6 = 42 * 10^6
42* 10^6 + 2 * 10^6 = 44 * 10^6
thus 6 million.
42* 10^6 + 2 * 10^6 = 44 * 10^6
thus 6 million.
