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A bit of logic.

9G + 16B = 25

60% of 25 = 15

To have our 15 we have to cut the B and to have 6 to obtain 15. The difference is 10. E is the answer
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I just set it up like this.

9/X marbles = .60 ==> solve for x equals 15 marbles. 25-10 = 15.
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9 green, 16 blue = 25 marbles
60% = 9 marbles , 100% = 15 marbles
so in 15 9 green and 10 blue
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I Just did it this way,
Since the bag should contain 60% green marbles and rest Blue Marbles,

x/(9+16) = 60% ==> x= 15 ==> 9+ 6 , so 10 blue marbles will be removed.
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Hi All,

This question is rooted in basic arithmetic. Since the question asks how many marbles need to be removed and the answers ARE numbers, we can TEST THE ANSWERS until we find the one that "fits."

To start, we have a bag of marbles....
9 green
16 blue
25 total

We're asked to remove blue marbles until the green marbles make up 60% of the bag....

Right now, green marbles make up 9/25 = 36% of the bag, so we clearly need to remove a bunch of blue marbles to change this percentage. Looking at the answers, I'd TEST one of the larger options first...

Let's TEST D....

IF 9 blue marbles were removed, then we'd have...
9 green
7 blue
16 total
9/16 is NOT 60% exactly, but it's pretty close....

Let's TEST E...

IF 10 blue marbles were removed, then we'd have...
9 green
6 blue
15 total
9/15 IS 60%, so this MUST be the answer!

Final Answer:
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Hi All,

This question is rooted in basic arithmetic. Since the question asks how many marbles need to be removed and the answers ARE numbers, we can TEST THE ANSWERS until we find the one that "fits."

To start, we have a bag of marbles....
9 green
16 blue
25 total

We're asked to remove blue marbles until the green marbles make up 60% of the bag....

Right now, green marbles make up 9/25 = 36% of the bag, so we clearly need to remove a bunch of blue marbles to change this percentage. Looking at the answers, I'd TEST one of the larger options first...

Let's TEST D....

IF 9 blue marbles were removed, then we'd have...
9 green
7 blue
16 total
9/16 is NOT 60% exactly, but it's pretty close....

Let's TEST E...

IF 10 blue marbles were removed, then we'd have...
9 green
6 blue
15 total
9/15 IS 60%, so this MUST be the answer!

Final Answer:
GMAT assassins aren't born, they're made,
Rich
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enigma123
The contents of a bag of marbles consist of 9 green marbles and 16 blue marbles. How many blue marbles must be removed so that 60% of the marbles in the bag will be green?

(A) 1
(B) 6
(C) 7
(D) 9
(E) 10

Relatively easy question and I think I have a problem with the concept. Can someone please explain?


This question is noting but a foul question. Just apply your common sense. Blue marbles are more than green marbles. Now what you want to do. You want to make green marbles 60%. Just think. In order to do it is asked to remove some blue marbles. we don't know how many marbles we remove to meet the condition. if blue and green marbles are equal , i mean, 9/9............it is 50%......green 50% ...........blue is 50%..........therefore all the option A to D is out. Only option E is left.
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(9/(25-x))*100 = 60
900 = 60*(25-x)
900=1500 -60x
x=10
answer E
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enigma123
The contents of a bag of marbles consist of 9 green marbles and 16 blue marbles. How many blue marbles must be removed so that 60% of the marbles in the bag will be green?

(A) 1
(B) 6
(C) 7
(D) 9
(E) 10

Relatively easy question and I think I have a problem with the concept. Can someone please explain?

If 60% of the marbles in the bag must be green, then 40%, or ⅖, of the marbles will be blue. Letting n = the number of blue marbles to be removed, we can create the equation:

(16 - n)/(25 - n) = 2/5

80 - 5n = 50 - 2n

30 = 3n

10 = n

Alternate Solution:

Notice that, no matter how many blue marbles are removed, there are still 9 green marbles in the bag, and we want this number to be 60% of all the marbles. Thus, after the removal of blue marbles, there should be 9/0.6 = 15 marbles in the bag. Since there were 9 + 16 = 25 marbles in the bag to begin with, 25 - 15 = 10 blue marbles should be removed.

Answer: E
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enigma123
The contents of a bag of marbles consist of 9 green marbles and 16 blue marbles. How many blue marbles must be removed so that 60% of the marbles in the bag will be green?

(A) 1
(B) 6
(C) 7
(D) 9
(E) 10

GIVEN: Start with 9 green marbles and 16 blue marbles

Let x = the number of BLUE marbles to remove
So, the NEW number of blue marbles remaining = 16 - x
The number of green marbles remaining = 9

How many blue marbles must be removed so that 60% of the marbles in the bag will be green?
We want: (number of GREEN marbles)/(TOTAL number of marbles) = 60%
Rewrite as: (number of GREEN marbles)/(TOTAL number of marbles) = 3/5

Plug in values to get: (9)/(16 - x + 9) = 3/5
Simplify to get: (9)/(25 - x) = 3/5
Cross multiply to get: (5)(9) = 3(25 - x)
Expand to get: 45 = 75 - 3x
Keep going: -30 = -3x
Solve: x = 10

Answer: E

Cheers,
Brent
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enigma123
The contents of a bag of marbles consist of 9 green marbles and 16 blue marbles. How many blue marbles must be removed so that 60% of the marbles in the bag will be green?

(A) 1
(B) 6
(C) 7
(D) 9
(E) 10

GIVEN: Start with 9 green marbles and 16 blue marbles

Let x = the number of BLUE marbles to remove
So, the NEW number of blue marbles remaining = 16 - x
The number of green marbles remaining = 9

How many blue marbles must be removed so that 60% of the marbles in the bag will be green?
We want: (number of GREEN marbles)/(TOTAL number of marbles) = 60%
Rewrite as: (number of GREEN marbles)/(TOTAL number of marbles) = 3/5

Plug in values to get: (9)/(16 - x + 9) = 3/5
Simplify to get: (9)/(25 - x) = 3/5
Cross multiply to get: (5)(9) = 3(25 - x)
Expand to get: 45 = 75 - 3x
Keep going: -30 = -3x
Solve: x = 10

Answer: E

Cheers,
Brent
9=0.6X
X=15
15-9=6
So, the number of blue marbles has to be 6.
16-y=6
y= 10

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