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got to the right answer in 1 minute.

since we have rounded to the nearest cm, and we are asked for the maximum possible area, then we have to maximize the values of length and width.
7.5<L<8.5
5.5<W<6.5

suppose L = 8.4 and W=6.4

8.4*6.4=53.76. since we need to have a value around this number, only C fits in.

I tried 8.49 and 6.49. the value is 55.1001. since we put more 9's after the decimal points, the number will increase, but very very little. thus, it can't be B.
48 cannot be the maximum value, and everything below 48 as well.
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gmihir
The sides of a rectangular region measured to the nearest centimeter are 8 cm and 6 cm. Out of the following which is the largest possible value of actual area of rectangle ?

A. 48
B. 55.25
C. 52.29
D. 44
E. 41.25

If l’=8 and w’=6 are the rounded-to-integer values of the length and width of the rectangle, then according to the conventional rounding rule, the following must be true about the actual values:

7.5 ≤ l < 8.5

5.5 ≤ w < 6.5

Since all sides are positive in the inequalities above, we can multiply the corresponding sides to have:

(7.5)(5.5) ≤ lw < (8.5)(6.5)

41.25 ≤ lw < 55.25

We see that among the given choices, 52.29 is the largest possible value of the actual area.

Answer: C

(Note: The question stem should ask for the largest possible value of the actual area in square centimeters.)
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