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The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks


The ratio of spinsters to cats is 2 to 7. If there are 25 more cats than spinsters, how many spinsters are there?
A) 10
B) 12
C) 15
D) 18
E) 27

Let the common multiplier for ratio be x
Such that Cats = 7x and Spinsters be 2x
cats-spins = 7x - 2x = 5x

but cats are 25 more than spinsters

5x=25; x=5

Spinsters = 2x = 2*5 = 10

A is my choice
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phoenix9801
The Book does not show any answers. Hence I need to figure out if I have done them correctly or not. Please help me if you can. Would greatly appropriate it. Thanks

The ratio of spinsters to cats is 2 to 7. If there are 25 more cats than spinsters, how many spinsters are there?

A. 10
B. 12
C. 15
D. 18
E. 27

Given: \(\frac{spinsters}{cats}=\frac{2x}{7x}\) for some positive integer multiple \(x\). Also given that \(7x-2x=25\) --> \(x=5\) --> \(spinsters=2x=10\).

Answer: A.
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phoenix9801
The ratio of spinsters to cats is 2 to 7. If there are 25 more cats than spinsters, how many spinsters are there?

A. 10
B. 12
C. 15
D. 18
E. 27

Given ratio = S:C = 2:7.
The difference between the parts of the ratio = 7-2 = 5.
Since the actual difference between the number of cats and the number of spinsters is five times as great -- 25 -- each part of the ratio must be multiplied by a FACTOR OF 5:
S:C = (2*5) : (7*5) = 10:35, with the result that there are 25 more cats than spinsters.
Thus, S=10.

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Let Spinsters = s and Cats = c
s:c = 2:7
i.e. s/c=2/7
so 7s=2c

And c= 25 + s
Substituting, 7s = 50 + 2s
Therefore, s=10
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phoenix9801
The ratio of spinsters to cats is 2 to 7. If there are 25 more cats than spinsters, how many spinsters are there?

A. 10
B. 12
C. 15
D. 18
E. 27

This is how i solved

Let no of spinsters be x and cats = x+25

Therofre we now know x/ x+25 = 2/7 solve for x by cross multiplying

2x+50 = 7x ie X = 10 ie no of spinsters ans choice A
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