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aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

i would suggest to take num rather than doing it algerabically.

take 10.. when it divided by 7 it will have remainder 3..
So R=10..

S will also B 10..

Square of 10..=100

r2-s..100-10=90..

90 /7 ..u l have remained 6 ..

Hope it helps !
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aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

I was wondering if my approach is okay.. Here's my work.
r/7 = 3
s/7 = 3
r^2 - s / 7
Since everything is divided by 7, you can cancel all of those out.
R = S
R = 3
S = 3

so.. 3^2 - 3 = 6
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aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

i would suggest to take num rather than doing it algerabically.

take 10.. when it divided by 7 it will have remainder 3..
So R=10..

S will also B 10..

Square of 10..=100

r2-s..100-10=90..

90 /7 ..u l have remained 6 ..

Hope it helps !

That's correct. +1.

r^2 - s must yield the same reminder when divided by 7 for every r and s which satisfy the given conditions. Thus picking numbers would be the easiest way to deal with this question.
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aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

i would suggest to take num rather than doing it algerabically.

take 10.. when it divided by 7 it will have remainder 3..
So R=10..

S will also B 10..

Square of 10..=100

r2-s..100-10=90..

90 /7 ..u l have remained 6 ..

Hope it helps !

That's correct. +1.

r^2 - s must yield the same reminder when divided by 7 for every r and s which satisfy the given conditions. Thus picking numbers would be the easiest way to deal with this question.


Thanks for kudos ..MATH GURU..:)..
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Or alternatively
r = 7x + 3
s = 7y + 3
r^2 = 49x^2+ 7*3*2 + 9
r^2 - s = 7*7x^2+ 7*3*2 + 9 - 7y + 3 = 7(7x^2+6) +6 = 7Q + 6
Remainder is 6
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Bunuel

r^2 - s must yield the same reminder when divided by 7 for every r and s which satisfy the given conditions. Thus picking numbers would be the easiest way to deal with this question.

this doesn't seem to work when r=3 and s=10
not sure why
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Bunuel

r^2 - s must yield the same reminder when divided by 7 for every r and s which satisfy the given conditions. Thus picking numbers would be the easiest way to deal with this question.

this doesn't seem to work when r=3 and s=10
not sure why

If r = 3 and s = 10, then r^2 - s = -1. The remainder when -1 id divided by 7 is also 6.
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Since we have absolute values in answer, plugged in 10,17 so 100 - 17 = 83, reminder 6
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sanjoo
aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

i would suggest to take num rather than doing it algerabically.

take 10.. when it divided by 7 it will have remainder 3..
So R=10..

S will also B 10..

Square of 10..=100

r2-s..100-10=90..

90 /7 ..u l have remained 6 ..

Hope it helps !

Hi Sanjoo,

In this method, how do we know if R=S?
If R=10, S can be 3 or 10 or 17 etc, isn't it?
If S=3, then r2-s=100-9=91, 91/7 gives a remainder of 0.
If S=10, then as per the calculation, we get a remainder of 6.
Wondering if I missed something here?
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pdavulur
sanjoo
aeros232
52. When integer r is divided by 7, the remainder is 3. When integer s is divided by 7, the remainder is 3 also. What is the remainder when r^2 - s is divided by 7?


a. 2
b. 3
c. 4
d. 5
e. 6

i would suggest to take num rather than doing it algerabically.

take 10.. when it divided by 7 it will have remainder 3..
So R=10..

S will also B 10..

Square of 10..=100

r2-s..100-10=90..

90 /7 ..u l have remained 6 ..

Hope it helps !

Hi Sanjoo,

In this method, how do we know if R=S?
If R=10, S can be 3 or 10 or 17 etc, isn't it?
If S=3, then r2-s=100-9=91, 91/7 gives a remainder of 0.
If S=10, then as per the calculation, we get a remainder of 6.
Wondering if I missed something here?

Hi pdavulur,
Please check the highlighted part.
You have subtracted \(r^2-s^2 \)instead of \(r^2-s\)
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Thanks Nabneet for calling it out :)

I definitely missed that!
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