np1986
Bunuel
gmatbull
James and Henry are at the northwest corner of their business school’s football field, which is a rectangle 300 ft long and 160 ft wide. James walks in a straight line directly to the southeast corner of the field. If Henry walks 180 ft down the west side of the field and then walks in a straight line directly to the southeast corner of the field, how many feet farther, to the nearest 10 ft, will Henry walk than James?
A. 20
B. 40
C. 80
D. 120
E. 140
Look at the diagram below:
Attachment:
Football field.png
The distance covered by James (AD) is shown in blue and it equals to \(\sqrt{300^2+160^2}=\sqrt{10^2(30^2+16^2)}=10*\sqrt{1156}=340\);
The distance covered by Henry (AB+BD) is shown in red and it equals to \(180+\sqrt{120^2+160^2}=180+\sqrt{10^2(12^2+16)^2}=180+10\sqrt{400}=380\);
The difference is 380-340=40.
Answer: B.
Is there an alternative (and quicker) way to get the solution without doing the calculations, e.g. through ballparking and eliminating answer options?
Actually, the method shown by Bunuel is quite straight forward and you don't need to do any calculations if you just remember some of your pythagorean triplets (and that's why we suggest you to remember them!)
BC = 120, CD = 160
BC:CD = 3:4
Does it remind you of 3-4-5 triplet?
120 is 3*40 and 160 is 4*40 so BD will be 5*40 = 200
So Henry traveled 180 + 200 = 380
AB = 160, BD = 300
So AB:BD = 8:15
Remember 8-15-17? (the third triplet after 3-4-5 and 5-12-13)
Hence AD should be 17*20 = 340
James traveled 340
Difference = 40
I have seen the following triplets coming in handy:
( 3, 4, 5 ) ( 5, 12, 13) ( 8, 15, 17) ( 7, 24, 25)
(20, 21, 29) and ( 9, 40, 41)